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emmasim [6.3K]
2 years ago
5

Describe J.J Thomson's plum pudding model,and explain how it compares to the modern day atomic theory.​

Physics
2 answers:
juin [17]2 years ago
8 0

The correct answer to this open question is the following.

The J.J Thomson's plum pudding model establishes that when he researched the atom, he found that electrons are positively charged. Because he observed that electrons were embedded like plums. Electrons are negative. However, compared to the modern-day atomic theory, scientist Ernest Rutherford established that the space between an atom is empty, the nucleus of the atom is positive, and negative electrons have fixed motion paths.

natita [175]2 years ago
4 0

Answer:

J J Thomson's plum pudding model indicated that <em>the negative electrons represented the raisins in the pudding and the dough contained the positive charge.</em>

Explanation:

Thomson discovered electron in 1897 and demonstrated that cathode rays were negatively charged. In addition, he also studied positively charged particles in neon gas. Thomson realized that the accepted model of an atom did not account for negatively or positively charged particles. Therefore, he proposed a model of the atom which he likened to plum pudding.  The model indicate that

<em>The negative electrons represented the raisins in the pudding and the dough contained the positive charge. </em>

Thomson's model of the atom did explain some of the electrical properties of the atom due to the electrons, but failed to recognize the positive charges in the atom as particles.

<em>The current model indicate the presence of the  a positively charged center of the atom that is denser than the rest of it called the nucleus. This dense center is made up of positively charged protons and neutrally charged neutrons. Around the outside of the nucleus the electrons are organized on rings. These electrons are arranged in  a certain pattern that is the same for all atoms.</em>

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Does a photon emitted by a higher-wattage red light bulb have more energy than a photon emitted by a lower-wattage red bulb
Liono4ka [1.6K]

Answer:

The energy of these two photons would be the same as long as their frequencies are the same (same color, assuming that the two bulbs emit at only one wavelength.)

Explanation:

The energy E of a photon is proportional to its frequency f. The constant of proportionality is Planck's Constant, h. This proportionality is known as the Planck-Einstein Relation.

E = h\, f.

The color of a beam of visible light depends on the frequency of the light. Assume that the two bulbs in this question each emits light of only one frequency (rather than a mix of light of different frequencies and colors.) Let f_{1} and f_{2} denote the frequency of the light from each bulb.

If the color of the red light from the two bulbs is the same, those two bulbs must emit light at the same frequency: f_{1} = f_{2}.

Thus, by the Planck-Einstein Relation, the energy of a photon from each bulb would also be the same:

h\, f_{1} = h\, f_{2}.

Note that among these two bulbs, the brighter one appears brighter soley because it emits more photons per unit area in unit time. While the energy of each photon stays the same, the bulb releases more energy by emitting more of these photons.

6 0
2 years ago
A train car has a mass of 10,000 kg and is moving at +3.0 m/s. It strikes an identical train car that is at rest. The train cars
jolli1 [7]

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Explanation:

Edg

7 0
3 years ago
The collision between a hammer and a nail can be considered to be approximately elastic. estimate the kinetic energy acquired by
Setler [38]

Here we can use momentum conservation as in this type of collision there is no external force on it

m_1v_{1i} + m_2v_{2i} = m_1 v_{1f} + m_2v_{2f}

now here we can say

m_1 = 10 g

v_{1i} = 0

m_2 = 550 g

v_{2i} = 3.5 m/s

now here we can say

10*0 + 550 * 3.5 = 10 v_{1f} + 550 v_{2f}

192.5 = v_{1f} + 55 v_{2f}

now by coefficient of restitution

for elastic collision we know that e = 1

v_{2f} - v_{1f} = e(v_{1i} - v_{2i})

v_{2f} - v_{1f} = 0 - 3.5

now by solving the two equation

56v_{2f} = 189

v_{2f} = 3.375 m/s

also we know that

v_{1f} = v_{2f} + 3.5 = 3.375 + 3.5 = 6.875 m/s

so final speed of the nail is 6.875 m/s


6 0
2 years ago
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