The conservation of momentum states that the total momentum in a system is constant if there is no external force acting on the system. The total momentum in the gun bullet system is 0 so it must stay that way.
The momentum of the bullet is mv = 0.015*500=7.5
The momentum of the gun must be the same to keep the total momentum of the system equal to zero, so we know that p = 7.5 for the gun.
Substituting this in we get:
7.5=3.1x
x=7.5/3.1
x=2.42
So the speed of the gun is 2.4m/s.
The potential difference across a and b is 15 v. determine the electrical charge on the 3 μf capacitor will be 45 *
C
Capacitance, property of an electric conductor, or set of conductors, that is measured by the amount of separated electric charge that can be stored on it per unit change in electrical potential. Capacitance also implies an associated storage of electrical energy.
Charge (Q) stored in a capacitor is the product of its capacitance (C) and the voltage (V) applied to it. The capacitance of a capacitor should always be a constant, known value. So we can adjust voltage to increase or decrease the cap's charge. More voltage means more charge, less voltage... less charge.
charge = capacitance * voltage
Q = CV
= 3 *
* 15 v
= 45 *
C
To learn more about capacitance here
brainly.com/question/14746225
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No cluuuueee :/ sowwwwyyy but good luck
The De Broglie wavelength of the electron is
![\lambda=34.0 nm=34 \cdot 10^{-9} m](https://tex.z-dn.net/?f=%5Clambda%3D34.0%20nm%3D34%20%5Ccdot%2010%5E%7B-9%7D%20m)
And we can use De Broglie's relationship to find its momentum:
![p= \frac{h}{\lambda}= \frac{6.6 \cdot 10^{-34} Js}{34 \cdot 10^{-9} m}=1.94 \cdot 10^{-26} kg m/s](https://tex.z-dn.net/?f=p%3D%20%5Cfrac%7Bh%7D%7B%5Clambda%7D%3D%20%5Cfrac%7B6.6%20%5Ccdot%2010%5E%7B-34%7D%20Js%7D%7B34%20%5Ccdot%2010%5E%7B-9%7D%20m%7D%3D1.94%20%5Ccdot%2010%5E%7B-26%7D%20kg%20m%2Fs%20%20)
Given
![p=mv](https://tex.z-dn.net/?f=p%3Dmv)
, with m being the electron mass and v its velocity, we can find the electron's velocity:
![v= \frac{p}{m}= \frac{1.94 \cdot 10^{-26} kgm/s}{9.1 \cdot 10^{-31} kg}= 2.13 \cdot 10^4 m/s](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7Bp%7D%7Bm%7D%3D%20%5Cfrac%7B1.94%20%5Ccdot%2010%5E%7B-26%7D%20kgm%2Fs%7D%7B9.1%20%5Ccdot%2010%5E%7B-31%7D%20kg%7D%3D%20%202.13%20%5Ccdot%2010%5E4%20m%2Fs)
This velocity is quite small compared to the speed of light, so the electron is non-relativistic and we can find its kinetic energy by using the non-relativistic formula: