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scZoUnD [109]
3 years ago
12

A rectangle has a perimeter of 16 feet. What is a possible length and width for the rectangle? A rectangle has a perimeter of 16

feet. What is a possible length and width for the rectangle? A rectangle has a perimeter of 16 feet. What is a possible length and width for the rectangle?
Mathematics
1 answer:
matrenka [14]3 years ago
4 0

Answer: width 2.5 length 4

Step-by-step explanation:

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The point P(x,y) lies on the terminal side of an angle θ = -60° in standard posistion. What are the signs of the values of x and
lyudmila [28]

Answer:

x positive, y negative

Step-by-step explanation:

-60 is the 4th quadrant of the unit circle ( negative angles go clockwise from 0), so  the x value is positive and the y value is negative.

3 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
FIND THE VOLUME STEP BY STEP
nalin [4]

Answer:

396 ft^{3}

Step-by-step explanation:

Okay, so first we will find the triangle area.

9 * 8 = 72/2 = 36.

Now multiply this by 11 (the width of the prism)

36 * 11 = 396 ft^{3}

7 0
3 years ago
1/5 of 25 = 25 divided by 5=
vitfil [10]
5 because 25 divided by 5 is 5
5 0
3 years ago
Solve for y. -13=4y+3
mina [271]

Answer:

y = -4

Explanation:

The initial expression is:

-13 = 4y + 3

So, we need to substract 3 from both sides of the equation:

-13 - 3 = 4y + 3 - 3

-16 = 4y

Then, dividing both sides by 4, we get:

-16/4 = 4y/4

-4 = y

Therefore, the solution of the system is y = - 4.

4 0
1 year ago
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