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2 years ago

Draw and label a diagram of a pulley system with a velocity ratio of 5

Physics

1 answer:

tensa zangetsu [6.8K]2 years ago

7 0

Why don’t you try and draw one, post it and I can tell you if it’s right. Basically use 5 pulleys. 3 and 2

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If you are traveling at 75 km/h how long will it take to travel 32 km?

Oksi-84 [34.3K]

Answer:

This would be 24 minutes

Explanation:

7 0

3 years ago

the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on

aleksandr82 [10.1K]

Answer:

your answer is here 180

Explanation:

900/2.5 * 2 = 180

6 0

1 year ago

Read 2 more answers

How does the sun rise and set

MatroZZZ [7]

Answer:

c. earth rotates on it tilted axis and orbit around the sun at the same time

Explanation:

Earth rotation can be defined as the amount of time taken by planet earth to complete its spinning movement on its axis.

This ultimately implies that, the rotation of earth refers to the time taken by earth to rotate once on its axis. One spinning movement of the earth on its axis takes approximately 24 hours to complete with respect to the sun. Thus, this makes us to experience day and night (sun rise and sun set) due to the rotation of planet about its axis.

Hence, the sun rise and set because the earth rotates on it tilted axis and orbit around the sun at the same time

8 0

3 years ago

A particular coaxial cable is comprised of inner and outer conductors having radii 1 mm and 3 mm respectively, separated by air.

noname [10]

Answer:

The value is $\rho_s = 4.026 *10^{-6} \ C/m^2$

Explanation:

From the question we are told that

The radius of the inner conductor is $r_1 = 1 \ mm = 0.001 \ m$

The radius of the outer conductor is $r_2 = 3 \ mm = 0.003 \ m$

The potential at the outer conductor is $V = 1.5 kV = 1.5 *10^{3} \ V$

Generally the capacitance per length of the capacitor like set up of the two conductors is

$C= \frac{2 * \pi * \epsilon_o }{ ln [\frac{r_2}{r_1} ]}$

Here $\epsilon_o$ is the permitivity of free space with value $\epsilon_o = 8.85*10^{-12} C/(V \cdot m)$

=> $C= \frac{2 * 3.142 * 8.85*10^{-12} }{ ln [\frac{0.003}{0.001} ]}$

=> $C= 50.6 *10^{-12} \ F/m$

Generally given that the potential of the outer conductor with respect to the inner conductor is positive it then mean that the outer conductor is positively charge

Generally the line charge density of the outer conductor is mathematically represented as

$\rho_l = C * V$