If this pendulum is situated in an elevator that is moving upward at a speed of 9.00 m/s2, the period of its minor oscillations is 4.34s.
<h3>One oscillation is it a period?</h3>
Period is equal to the length of one oscillation.
T. T . The frequency is the number of oscillations that occur in one second.
<h3>Short answer: How long does a pendulum swing?</h3>
A simple pendulum's period is: The symbol "T" stands for the period of time needed by the pendulum to complete one complete oscillation. The length of a basic pendulum: It is described as the distance the pendulum moves away from equilibrium and toward one side.
Since the elevator's oscillations for this pendulum are situated there and it is climbing at a 9.0 mph,
use G = 9.8 + 9.0 = 18.8 m/s²
Period T=2π√(L/G)
T= 2π√(9/18.8)
T=4.34s
To know more about oscillation visit:-
brainly.com/question/29273618
#SPJ4
Answer:
The work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.
Explanation:
Given;
potential difference between the plates, V = 10 V
length of each square side of the plates, L = 20 cm = 0.2 m
area of the plates, A = 0.2 x 0.2 = 0.04 m²
separation of the plates, d = 3 cm = 0.03 m
The work done in bringing the plates together is calculated as;
W = ¹/₂qV

Therefore, the work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.
Answer:
k = 86,646,076.92 J
Explanation:
We know that:
K = 
where K is the kinetic energy, I is the moment of inertia and W is the angular velocity.
First we have to find the I with the equation:
I = 
where M is the mass and R the radius of the cylinder.
so:
I = 
I = 365.04 kg*m^2
Now we replace all the data in the first equation as:
K = 
K = 
k = 86,646,076.92 J