A 6 cm diameter drill bit is used to drill a cylindrical hole through the middle of a sphere of radius 5 cm. What is the volume
1 answer:
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A)
The radius of the oil droplet is half of its diameter:
Assuming the droplet is spherical, its volume is given by
The density of the droplet is
Therefore, the mass of the droplet is equal to the product between volume and density:
B)
The potential difference across the electrodes is
and the distance between the plates is
So the electric field between the electrodes is
The droplet hangs motionless between the electrodes if the electric force on it is equal to the weight of the droplet:
So, from this equation, we can find the charge of the droplet:
C) Surplus of 9 electrons
The droplet is hanging near the upper electrode, which is positive: since unlike charges attract each other, the droplet must be negatively charged. So the real charge on the droplet is
we can think this charge has made of N excess electrons, so the net charge is given by
where
is the charge of each electron
Re-arranging the equation for N, we find:
so, a surplus of 9 electrons.