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notsponge [240]
3 years ago
6

Chemical equation=CH4 + O2 = CO2 + H2O.

Chemistry
1 answer:
tankabanditka [31]3 years ago
4 0

Answer:

1.The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction. The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction.The combustion of methane or octane is exothermic; it releases energy. CH4 + 2 O2 → CO2 + 2 H2O + energy The energies of the products are lower than the energiies of the reactants.

Explanation:

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Which star has the highest surface temperature
Mashcka [7]

Answer:

The blue star is the hottest star.

Explanation:

Red stars are cooler than the sun, with surface temperatures of 3,500 K for a bright red star and 2,500 K for a dark red star. The hottest stars are blue, with their surface temperatures falling anywhere between 10,000 K and 50,000 K

8 0
3 years ago
Read 2 more answers
CaCO3(s) ∆→CaO(s) + CO2(g).
sveta [45]

Answer:

74.9%.

Explanation:

Relative atomic mass data from a modern periodic table:

  • Ca: 40.078;
  • C: 12.011;
  • O: 15.999.

What's the <em>theoretical</em> yield of this reaction?

In other words, what's the mass of the CO₂ that should come out of heating 40.1 grams of CaCO₃?

Molar mass of CaCO₃:

M(\text{CaCO}_3) = 40.078 + 12.011 + 3 \times 15.999 = 100.086\;\text{g}\cdot\text{mol}^{-1}.

Number of moles of CaCO₃ available:

\displaystyle n(\text{CaCO}_3) =\frac{m}{M} = \frac{40.1}{100.086} = 0.400655\;\text{mol}.

Look at the chemical equation. The coefficient in front of both CaCO₃ and CO₂ is one. Decomposing every mole of CaCO₃ should produce one mole of CO₂.

n(\text{CO}2) = n(\text{CaCO}_3)= 0.400655\;\text{mol}.

Molar mass of CO₂:

M(\text{CO}_2) = 12.011 + 2\times 15.999 = 44.009\;\text{g}\cdot\text{mol}^{-1}.

Mass of the 0.400655 moles of \text{CO}_2 expected for the 40.1 grams of CaCO₃:

m(\text{CO}_2) = n\cdot M = 0.400655 \times 44.009 = 17.632\;\text{g}.

What's the <em>percentage</em> yield of this reaction?

\displaystyle \textbf{Percentage}\text{ Yield} = \frac{\textbf{Actual}\text{ Yield}}{\textbf{Theoretical}\text{ Yield}}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} = \frac{13.2}{17.632}\times 100\%\\\phantom{\textbf{Percentage}\text{ Yield}} =74.9\%.

7 0
3 years ago
100 cm3 of the copper sulfate solution contains 1.8 g of copper sulfate.
elixir [45]

Answer:

The mass of copper sulfate in 25 cm³ of the copper sulfate solution is 0.45 g

Explanation:

The given parameters are;

The volume of the copper sulfate solution = 100 cm³

The mass of the copper sulfate in the solution = 1.8 g

Therefore, the mass of copper sulfate in 25 cm³ of the solution is given as follows;

The mass of copper sulfate in 100 cm³ of the solution = 1.8 g

The mass of copper sulfate in 1 cm³ of the solution  = 1.8 g/100 = 0.018 g

Therefore;

The mass of copper sulfate in 25 × 1 = 25 cm³ of the solution, m  = 25×0.018 g = 0.45 g

∴ The mass of copper sulfate in 25 cm³ of the solution, m = 0.45 g

8 0
3 years ago
How will the properties of a biological membrane change if the fatty acid tails of the phospholipids are converted from saturate
kumpel [21]
Some of the properties that will change as the biological membrane composed primarily of phospholipids change from the saturated to unsaturated fatty acid tails of the phospholipid would include, permeability of the membrane, this will cause the membrane to be more fluid and not remain as controlling of the materials. The membrane will ultimately become poor in regulating ions and other materials from coming into the cell, as the phospholipids are not tightly packed due to them being unsaturated and having carbon double bonds within them. This can also affect the overall shape of the plasma membrane as well, causing it to be not as structured, and more fluid,
7 0
3 years ago
you do 185 j of work pulling a cart up a ramp. if the ramp does 153 j of work what is the efficient of the ram
egoroff_w [7]
Efficiency of the ram is calculated by dividing the work done by the work or energy that is exerted to do so. This is calculated through the equation,

     S = ((Wout) / (Win)) x 100%

Substiuting the known values to the equation.

    S = (153 J)/(185 J) x 100%

Efficiency = 82.7%. 
7 0
4 years ago
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