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Soloha48 [4]
3 years ago
5

Plz di all plz i will give brainest and thanks to best answer do it right

Physics
1 answer:
Inga [223]3 years ago
7 0

Answer:

area 4

Explanation:

area 4 has low pressure

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Answer:

it is zero

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HELP MEEEEE!!!!!!!!!!A student make a drawing of an aluminum atom.Which of these should the student show in the nucleus of the a
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A hollow sphere of radius 0.200 m, with rotational inertia I = 0.0484 kg·m2 about a line through its center of mass, rolls witho
d1i1m1o1n [39]

Answer:

Part a)

KE_r = 8 J

Part b)

v = 3.64 m/s

Part c)

KE_f = 12.7 J

Part d)

v = 2.9 m/s

Explanation:

As we know that moment of inertia of hollow sphere is given as

I = \frac{2}{3}mR^2

here we know that

I = 0.0484 kg m^2

R = 0.200 m

now we have

0.0484 = \frac{2}{3}m(0.200)^2

m = 1.815 kg

now we know that total Kinetic energy is given as

KE = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2

KE = \frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{R})^2

20 = \frac{1}{2}(1.815)v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2

20 = 1.5125 v^2

v = 3.64 m/s

Part a)

Now initial rotational kinetic energy is given as

KE_r = \frac{1}{2}I(\frac{v}{R})^2

KE_r = \frac{1}{2}(0.0484)(\frac{3.64}{0.200})^2

KE_r = 8 J

Part b)

speed of the sphere is given as

v = 3.64 m/s

Part c)

By energy conservation of the rolling sphere we can say

mgh = (KE_i) - KE_f

1.815(9.8)(0.900sin27.1) = 20- KE_f

7.30 = 20 - KE_f

KE_f = 12.7 J

Part d)

Now we know that

\frac{1}{2}mv^2 + \frac{1}{2}I(\frac{v}{r})^2 = 12.7

\frac{1}{2}(1.815) v^2 + \frac{1}{2}(0.0484)(\frac{v}{0.200})^2 = 12.7

1.5125 v^2 = 12.7

v = 2.9 m/s

8 0
4 years ago
What is the demand for resources, such as food, water, and shelter.
andrey2020 [161]
The demand for these things is very high. Everyone wants to have shelter, water, and food. However the demand for shelter is higher because water and food are more accessible.
3 0
3 years ago
A boat moving at 7.8 km/hr relative to the water is crossing a river 3.5 km wide in which the current is flowing at 2.8 km/hr. A
Free_Kalibri [48]

Answer:\theta =21.03^{\circ}

Explanation:

Given

velocity of boat with respect to river =7.8 km/hr

velocity of river is 2.8 km/hr

River is 3.5 km wide

Suppose boat leaves at an angle of \theta  with vertical such that it reaches exactly opposite end of initial Point

Therefore

7.8\sin \thetacomponent will balance the river Flowso that sin component helps to cross the river

7.8\sin \theta =2.8

\sin \theta =0.3589

\theta =sin^{-1}(0.3589)

\theta =21.03^{\circ}

8 0
3 years ago
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