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3 years ago

What is the initial velocity and final velocity h

Physics

1 answer:

IceJOKER [234]3 years ago

8 0

Answer:

initial velocity =starting velocity

final velocity=last velocity

keep in mind the fact that velocity is a vector quantity it also has a direction

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A light bulb has a resistance of 100 ohms. If a current of 1.2 amps is going through it, calculate

inysia [295]

Answer: 120 volts

Explanation:

5 0

3 years ago

A car is parked on a cliff overlooking the ocean on an incline that makes an angle of 24.0° below the horizontal. The negligent

tensa zangetsu [6.8K]

Answer:

(a): The car's relative position to the base of the cliff is x= 32.52m.

(b): The lenght of the car in the ir is tfall= 1.78 sec.

Explanation:

Vo= 0

V= ?

d= 50m

h= 30m

a= 4 m/s²

t= √(2*d/a)

t= 5 sec

V= a*t

V= 20 m/s

Vx= V * cos(24º)

Vx= 18.27 m/s

Vy= V* sin(24º)

Vy= 8.13 m/s

h= Vy*t + g*t²/2

clearing t:

tfall= 1.78 sec (b)

x= Vx * tfall

x= 32.52 m (a)

4 0

4 years ago

A nuclear accident (intentional or unintentional) can cause significant harm to those living nearby or at a distance. Harmful le

MrRissso [65]

Answer:Explained

Explanation:

Invisible gamma radiation does not transmit through Air or through contact thus standard precautions can encompasses more than person-to-person contamination.

Some Standard Precautions are

Hand Hygiene

Use Alcohol based hand disinfectant and always use gloves.

Use Eye shields,Gowns,face shields .

3 0

3 years ago

Newton’s first law describes the tendency calles

beks73 [17]

The first law is about force or push and pull

5 0

3 years ago

Read 2 more answers

The escape velocity is defined to be the minimum speed with which an object of mass m must move to escape from the gravitational

s344n2d4d5 [400]

Answer:

v = √2G $M_{earth}$ / R

Explanation:

For this problem we use energy conservation, the energy initiated is potential and kinetic and the final energy is only potential (infinite r)

Eo = K + U = ½ m1 v² - G m1 m2 / r1

Ef = - G m1 m2 / r2

When the body is at a distance R> Re, for the furthest point (r2) let's call it Rinf

Eo = Ef

½ m1v² - G m1 $M_{earth}$ / R = - G m1 $M_{earth}$ / R

v² = 2G $M_{earth}$ (1 / R - 1 / Rinf)

If we do Rinf = infinity 1 / Rinf = 0

v = √2G $M_{earth}$ / R

Ef = = - G m1 m2 / R

The mechanical energy is conserved

Em = -G m1 $M_{earth}$ / R

Em = - G m1 $M_{earth}$ / R

R = int ⇒ Em = 0

6 0

3 years ago