The law applied here is Hooke's Law which describes the force exerted by the spring with a given distance. The equation for this is F = kΔx, where F is the force in Newtons, k is the spring constant in N/m while Δx is the displacement in meters.
If you want to find work done by a spring, this can be solved by using differential equations. However, derived equations are already ready for use. The equation is
W = k[{x₂-x₁)² - (x₁-xn)²],
where
xn is the natural length
x₁ is the stretched length
x₂ is also the stretched length when stretched even further than x₁
In this case xn =x₁. So, that means that (x₁-xn) = 0 and (x₂-x₁) = 11 cm or 0.11 m.
Then, substituting the values,
2 J = k (0.11² -0²)
k = 165.29 N/m
Finally, we use the value of k to the Hooke's Law to determine the Force.
F = kΔx = (165.29 N/m)(0.11 m)
F = 18.18 Newtons
<h2><u><em>Well, you see, that depends. </em></u></h2><h2><u><em>The firsy thing we have to tak intp account is the angle at witch the sun's rays hit the earth, and that fact can make all the difference, seeing as it does discriminate against seasons. It's more likely that i the winter, a more drastic effect would talk.</em></u></h2><h2 /><h2 /><h2 /><h2>oωo</h2>
Answer:
The tension force in the supporting cables is 7245N
Explanation:
There are two forces acting on the elevator: the force of gravity pointing down (+) with magnitude (elevator mass) x (gravitational acceleration), and the tension force of the cable pointing up (-) with an unknown magnitude F. The net force is the sum of these forces:
We are given the resulting acceleration along with the mass, i.e., we know the net force, allowing us to solve for F:
The tension force F in the supporting cables is 7245N
Answer:
Extraneous
Explanation:
Extraneous variables are any variables that you are not intentionally studying in your experiment or test
Answer:
not clear pic...but it's definitely not A)
