Answer:

Explanation:
It often helps to write the heat as if it were a reactant or a product in the thermochemical equation.
Then you can consider it to be 11018 "moles" of "kJ"
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
M_r: 32.00
2C₈H₁₈ + 25O₂ ⟶ 16CO₂ + 8H₂O + 11 018 kJ
n/mol: 7280
1. Moles of O₂
The molar ratio is 25 mol O₂:11 018 kJ

2. Mass of O₂

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Answer:
S = 1.1 × 10⁻⁹ M
Explanation:
NaCl is a strong electrolyte that dissociates according to the following expression.
NaCl(aq) → Na⁺(aq) + Cl⁻(aq)
Given the concentration of NaCl is 0.15 M, the concentration of Cl⁻ will be 0.15 M.
We can find the molar solubility (S) of AgCl using an ICE chart.
AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)
I 0 0.15
C +S +S
E S 0.15+S
The solubility product (Ksp) is:
Ksp = 1.6 × 10⁻¹⁰ = [Ag⁺].[Cl⁻] = S (0.15 + S)
If we solve the quadratic equation, the positive result is S = 1.1 × 10⁻⁹ M
Answer:
By strengthening the weak coral that is on the reef.
Answer:
The answer to your question is 160 g of Calcium
Explanation:
Data
mass of Calcium = ?
mass of Hydrogen = 8 g
reactant = HCl
Process
1.- Write the balanced chemical reaction
Ca + 2HCl ⇒ CaCl₂ + H₂
2.- Look for the atomic number of Calcium and hydrogen
Calcium = 40 g
Hydrogen = 1 x 2 = 2 g
3.- Use proportions to calculate the mass of calcium needed.
40 g of Calcium ---------------- 2 g of hydrogen
x ----------------- 8 g of hydrogen
x = (8 x 40) / 2
x = 320/2
x = 160 g of Calcium