Answer:
The answer for this is Green Rectangle.
Explanation:
The hue after effects theory suggests that as you glance away at a white background, you can see a <em>Green Rectangle</em> after looking at a bright red rectangle for a period of time.
All this is an after-image consequence. Afterimage is a form of optical illusion in which, even after exposure to the original image has ended, an picture appears to appear momentarily.
Answer:
10 dumbbells
Explanation:
First we need to calculate the gravity on the moon.
0.166 x 9.8 m/s² = 1.627 m/s² (the gravity is 0.166 times the Earth's gravity)
Taking this acceleration due to gravity, and multiplying it by the mass of a single dumbbell.
F = m x a
F = (225 kg) x (1.627 m/s²)
F = 366.075 N (the amount of force exerted by the dumbbell)
Taking the weightlifter's total upward force and dividing it by the force exerted by one dumbbell, we can calculate the amount of dumbbells that can be carried.
(3750 N) / (366.075 N)
= 10.24 dumbbells (but since there cannot be a fraction of a dumbbell, the answer is <u>10 dumbbells</u>).
Answer:
The answer to your question is:
a) t1 = 2.99 s ≈ 3 s
b) vf = 39.43 m/s
Explanation:
Data
vo = 10 m/s
h = 74 m
g = 9.81 m/s
t = ? time to reach the ground
vf = ? final speed
a) h = vot + (1/2)gt²
74 = 10t + (1/2)9.81t²
4.9t² + 10t -74 = 0 solve by using quadratic formula
t = (-b ± √ (b² -4ac) / 2a
t = (-10 ± √ (10² -4(4.9(-74) / 2(4.9)
t = (-10 ± √ 1550.4 ) / 9.81
t1 = (-10 + √ 1550.4 ) / 9.81 t2 = (-10 - √ 1550.4 ) / 9.81
t1 = (-10 ± 39.38 ) / 9.81 t2 = (-10 - 39.38) / 9.81
t1 = 2.99 s ≈ 3 s t2 = is negative then is wrong there are
no negative times.
b) Formula vf = vo + gt
vf = 10 + (9.81)(3)
vf = 10 + 29.43
vf = 39.43 m/s
The correct answer would be the first option. The process that would need more energy would be vaporizing 1 kg of saturated liquid water at a pressure of 1 atmosphere. This can be seen from the latent heat of vaporization of each system. For the saturated water at 1 atm, the latent heat is equal to 40.7 kJ per mole while, at 8 atm, the latent heat is equal to 36.4 kJ per mole. The latent heat of vaporization is the amount of heat needed in order to vaporize a specific amount of substance without any change in the temperature. As we can observe, more energy is needed by the liquid water at 1 atm.