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Verizon [17]
4 years ago
5

Which alkane would have a higher boiling point?a)ethaneb)pentanec)heptane

Chemistry
1 answer:
Whitepunk [10]4 years ago
6 0

Answer:

The correct answer is option c.

Explanation:

Alkanes with higher molecular mass has higher boiling point.

Thisis because when the molar mass of the alkanes increases the the surface area  increases with which van der Waals forces between the molecules of alkane also increase which increases the association of the molecules of with each other which results in increase in boiling point is observed.

The increasing order of the molar mass of the given alkanes;

C_2H_6

So out of ethane, pentane and heptane . Heptane has highest molecular mass with higher boiling point value. Where as ethane have the lowest value of boiling point.

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A nucleus is in the center of an atom and protons and neutrons are found inside there
3 0
4 years ago
Which of these is something whose construction MOST LIKELY would be determined by the government? A) An airport B) A golf club C
Amiraneli [1.4K]

Answer:

I would say an airport

Explanation:

why because it is ran by the government

8 0
3 years ago
Read 2 more answers
You have a 1.153 g sample of an unknown solid acid, HA, dissolved in enough water to make 20.00 mL of solution. HA reacts with K
Shalnov [3]

Answer:

The concentration of the unknown acid (HA) is 0.434M

The molar mass of HA is 13.3g/mole

Explanation:

DETERMINATION OF MOLARITY OF THE UNKNOWN ACID

CaVa/CbVb = Na/Nb

From the equation of reaction and at equivalence point, Na = Nb = 1

Therefore, CaVa = CbVb

Va (volume of acid solution) = 20mL = 20/1000 = 0.2L

Cb (concentration of KOH) = 0.715M

Vb (volume of KOH) = 12.15mL

Ca (concentration of acid) = CbVb/Va

Ca = 0.715M × 12.15mL/20mL = 0.434M

DETERMINATION OF MOLAR MASS OF HA

Number of moles of acid = concentration of acid × volume of acid solution in liters = 0.434 × 0.2 = 0.0868mole

Molar mass of HA = mass/number of moles = 1.153g/0.0868mole = 13.3g/mole

7 0
4 years ago
(A) H2SeO4(aq) + 2 Cl-(aq) + 2 H+(aq) → H2SeO3(aq) + Cl2(g) + H2O(l) (B) S8(s) + 8 O2(g) → 8 SO2(g) (C) 3 Br2(aq) + 6 OH-(aq) →
AVprozaik [17]

Answer:

C)

Explanation:

Oxidation occurs when the Nox number increases and a reduction occurs when the Nox number decreases. So, let's verify in which reaction the same reactant has elements that both occur after the reaction.

A) H₂SeO₄: H = +1, O = -2 (fixed)

Se: x +2*1 + 4*(-2) = 0

x + 2 - 8= 0

x = +6

Cl⁻: -1 (ions have Nox equal to its charge)

H⁺: +1

H₂SeO₃: H = + 1, O = -2

Se: x +2*1 + 3*(-2) = 0

x + 2 -6 = 0

x = + 4 (Se reduces)

Cl₂: Cl = 0 (simple molecule, so Cl oxides)

H₂O: H = +1, O = -2

B) S₈: S = 0

O₂: O = 0

SO₂: O = -2, S: x + 2*(-2) = 0 -> x = +4 (S oxides and O reduces)

C) Br₂: Br = 0

OH⁻ : O = -2, H = +1

Br⁻ = -1 (Br reduces)

BrO₃⁻: O = -2, Br: x +3x(-2) = -1 -> x = +5 (Br oxides)

H₂O: H = +1, O = -2

D) Ca²⁺: Ca = +2

SO₄²⁻: O = -2, S: x +4*(-2) = -2 -> x = +6

CaSO₄: O = -2, S = +6, Ca = +2

E) PtCl₄: Cl = -1 (fixed), Pt: x + 4*(-1) = 0 -> x = +4

Cl⁻: Cl = -1

PtCl₆²⁻: Cl = -1, Pt = x + 6*(-1) = -2 -> x = +4

So, only in letter C Br₂ is undergoes both oxidation and reduction.

4 0
3 years ago
HELP SOMEONE PLEASE I WILL GIVE BRAINLIST I NEED IT NOW PLZ! LOOK AT THE IMAGE ABOVE TO ANSWER
MAVERICK [17]

Answer:

its endothermic .

because your using a cooling process instead of a heating process if it was a heating process it would be exothermic

4 0
3 years ago
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