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wel
3 years ago
7

Strontium crystallizes in a face-centered cubic unit cell having an edge length of 77.43 pm. What is the atomic radius of stront

ium (in picometers) based on this structure
Chemistry
1 answer:
kiruha [24]3 years ago
5 0

Answer:

Atomic radius of Strontium is 27.38pm

Explanation:

In a face-centered cubic structure, the edge, a, could be obtained using pythagoras theorem knowing the hypotenuse of the unit cell, b, is equal to 4r:

a² + a² = b² = (4r)²

2a² = 16r²

a = √8 r

As edge length of Strontium is 77.43pm:

77.43pm / √8 = r

27.38pm = r

<h3>Atomic radius of Strontium is 27.38pm</h3>

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Write a paragraph (5-7 sentences) describing pH and conductivity.
PilotLPTM [1.2K]

Answer:

pH is a measure of hydrogen ion concentration, a measure of the acidity or alkalinity of a solution. The pH scale usually ranges from 0 to 14. Aqueous solutions at 25°C with a pH less than 7 are acidic, while those with a pH greater than 7 are basic or alkaline. A pH level of 7.0 at 25°C is defined as "neutral" because the concentration of H3O+ equals the concentration of OH− in pure water. On the other hand, electrical conductivity is a non-specific measurement of the concentration of both positively and negatively charged ions within a sample. So the short answer to the question is as follows, the presence of any hydrogen ions present in a substance will impact the pH level and most probably influence conductivity levels. However, hydrogen ions make up only a small part of the ion concentration measured by a conductivity meter.

4 0
3 years ago
If our eyes could see a slightly wider region of the electromagnetic spectrum, we would see a fifth line in the Balmer series em
erica [24]

Answer: Wavelength  associated with the fifth line is 397 nm

Explanation:

E=\frac{hc}{\lambda}

\lambda = Wavelength of radiation

E= energy

For fifth line in the H atom spectrum in the balmer series will be from n= 2 to n=7.

Using Rydberg's Equation:

\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )\times Z^2

Where,

\lambda = Wavelength of radiation

R_H = Rydberg's Constant =10973731.6m^{-1}

n_f = Higher energy level = 7

n_i= Lower energy level = 2 (Balmer series)

Putting the values, in above equation, we get

\frac{1}{\lambda}=10973731.6\times \left(\frac{1}{2^2}-\frac{1}{7^2} \right )\times 1^2

\frac{1}{\lambda}=2.52\times 10^{6}m

\lambda}=3.97\times 10^{-7}m=397 nm      1nm=10^{-9}m

Thus wavelength λ associated with the fifth line is 397 nm

7 0
4 years ago
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joja [24]

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1mol requires 5.66KJ energy

13.5mol requires

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2 years ago
What is the mole ratio of NH3 to N2?
olga_2 [115]

answers : the mole ratio between NH3 : NH2 is 2:1

7 0
3 years ago
Solve for enthalpy of reaction.
densk [106]
What your question is unclear?
3 0
3 years ago
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