There are rules to assigning conventional oxidation numbers to some elements. For those unspecified, you can solve them. This is how you solve it.
*S8. Since this is in elemental form, its oxidation number is assigned as 0.
*H2S. H is assigned with +1. Since the compound is neutral, the overall charge is 0. So,
2(+1) + x = 0
x = -2
The charge of S here is -2.
*SO₂. O is assigned with (-2). Using the same procedure,
x + 2(-2) = 0
x = +2
The charge of S here is +2.
*H₂SO₃.
2(+1) + x + 3(-2) = 0
x = +4.
The charge of S here is +4.
*K₂SO₄. K is assigned with +1.
2(+1) + x + 4(-2) = 0
x = +6
The charge of S here is +6.
<em>The S with the highest oxidation number is the one in K₂SO₄.</em>
the mass of pure acetic acid in 250 ml of this solution is 100 gm
The type of atoms present in the chemical compound and the proportion or how many specific atoms are respect to other atoms in the chemical compound.
Answer:
Stretch band
Explanation:
Bc mechanical energy is the energy of movement so it’s all around us and so anything that moves us basically mechanical energy therefore a stretch band has mechanical energy
Moles of chlorine gas = 100/70.906 = 1.41 moles.
Therefore volume of Cl2 at STP = moles of Cl2 x 22.4 = 1.41 x 22.4 = 31.584 liters.
Hope this helps!