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Dmitrij [34]
3 years ago
11

The local weather station is predicting that a warm front will pass through Charlotte, NC in two days.

Chemistry
1 answer:
Nutka1998 [239]3 years ago
4 0

Answer:

C the temperature will increase.

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What is the formula for diblackur triorangide?
SashulF [63]

Answer:

stop trolling

Explanation:

this does not exist

7 0
3 years ago
N2+3H2=>>2NH3. If 6.72dm³ of each of Nitrogen and hydrogen (measured at S.T.P.) are made to produced Ammonium. Which of th
torisob [31]

Answer:

Hydrogen, 0,2 mol

Explanation:

V_{M} = 22, 4 l/mol

V (N_{2}) = 6,72 dm^{2} = 6,72 l

V (H_{2}) = 6,72 dm^{2} = 6,72 l

The formula is:

n = \frac{V}{V_{M} }

n  (N_{2}) = 6,72l /22,4 l/mol = 0,3 mol

n  (H_{2}) = 6,72l /22,4 l/mol = 0,3 mol (the same)

But from the equation we get a proportion that 1 mol  (N_{2}) - 3 mol (H_{2})

\frac{0,3}{1} > \frac{0,3}{3} (we have more hydrogen than is need for the reaction)

So there is excess of H_{2}

We only need  \frac{0,3}{3} = 0,1 mol (H_{2})

0,3 mol (hydrogen quantity we have) - 0,1 mol (hydrogen quantity we need for the reaction) = 0,2 mol (excess)

make me the brainliest

3 0
3 years ago
The rate of decomposition of radioactive radium is proportional to the amount present at any time. The half-life of radioactive
Naya [18.7K]

Answer:

\% \frac{A}{A_0}=75.9\%

Explanation:

Hello!

In this case, since the kinetics of the radioactive decay is assumed to be first-order, it is possible to use the following equation to quantify that change:

\frac{A}{A_0} =2^{-\frac{t}{t_{1/2}}

Thus, given the elapsed time, 635 years, and the half-life, 1599 years, we can compute the fraction of the present amount:

\frac{A}{A_0} =2^{-\frac{365years}{1599years}\\\\\frac{A}{A_0} =0.759

Thus, the percent is:

\% \frac{A}{A_0}=0.759*100\%\\\\ \% \frac{A}{A_0}=75.9\%

Best regards!

6 0
3 years ago
Which pair of compounds are isomers?
juin [17]
CH3OCH3 and C2H5OH are isomers. They have same molecular formula. But with another formation. 
4 0
4 years ago
Read 2 more answers
What is the value for (delta)G at 1000 K if (delta)H = -220 kJ/mol and (delta)S = -0.05 kJ/(molK)?
tankabanditka [31]
The system is isothermal, so we use the formula:
(delta)G = (delta)H - T (delta) S

Plugging in the given values:
(delta)G = -220 kJ/ mol - (1000K) (-0.05 kJ/mol K)
(delta)G = -170 kJ/mol

If we take a basis of 1 mol, the answer is
D. -170 kJ 
6 0
3 years ago
Read 2 more answers
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