Answer:
Hydrogen, 0,2 mol
Explanation:
= 22, 4 l/mol
V (
) = 6,72
= 6,72 l
V (
) = 6,72
= 6,72 l
The formula is:
n = 
n (
) = 6,72l /22,4 l/mol = 0,3 mol
n (
) = 6,72l /22,4 l/mol = 0,3 mol (the same)
But from the equation we get a proportion that 1 mol (
) - 3 mol (
)
(we have more hydrogen than is need for the reaction)
So there is excess of 
We only need
= 0,1 mol (
)
0,3 mol (hydrogen quantity we have) - 0,1 mol (hydrogen quantity we need for the reaction) = 0,2 mol (excess)
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Answer:

Explanation:
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In this case, since the kinetics of the radioactive decay is assumed to be first-order, it is possible to use the following equation to quantify that change:

Thus, given the elapsed time, 635 years, and the half-life, 1599 years, we can compute the fraction of the present amount:

Thus, the percent is:

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CH3OCH3 and C2H5OH are isomers. They have same molecular formula. But with another formation.
The system is isothermal, so we use the formula:
(delta)G = (delta)H - T (delta) S
Plugging in the given values:
(delta)G = -220 kJ/ mol - (1000K) (-0.05 kJ/mol K)
(delta)G = -170 kJ/mol
If we take a basis of 1 mol, the answer is
D. -170 kJ