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Lady bird [3.3K]
3 years ago
15

THE ONE WHO WILL ANSWER IT CORRECT WILL BE MARKED AS "BRAINLIST"....... If the radius of the orbit of a spaceship from the centr

e of the earth is twice the radius of the earth . then calculate the acceleration due to the gravity on space ship.​
Physics
1 answer:
jonny [76]3 years ago
5 0

Answer:

Explanation:

19116 being the distance from the centre of the earth to the point you want to check in metres. So after all that you get G = 1.0888m/second squared. Hope that helps you/ you should be able to pop in any height you want.

plz mark as brainliest

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8 0
3 years ago
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A carnot engine operates between two heat reservoirs at temperatures th and tc. an inventor proposes to increase the efficiency
Sonja [21]
The efficiency of the first Carnot engine is 
n1 = 1 - Th/T
The efficiency of the second Carnot engine is
n2 = 1 - T/Tc
The total efficiency of the engines put in series is
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What is the name of the part of the wave that is labeled -
tresset_1 [31]

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amplitude

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7 0
2 years ago
Which of the following statements concerning statistical probability is not true? A. Probability involves the level of certainty
Leto [7]
The answer to this is D. Probability levels for finding statistical significance increase as statistical power decreases. The statement concerning statistical probability is not true as this is d.

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8 0
3 years ago
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A 12000 kg railroad car is traveling at a 2 m/s when it strikes another 10000 kg railroad is at rest. If the car lock together w
zimovet [89]

The final speed is 1.09m\frac{m}{s}

Why?

To calculate the final speed, we need to know that we are working with an inelastic collision, it means that both bodies stick together after the colission. We can calculate the final speed of the bodies (if exists) using the following equation:

m_{1}v{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{f}

We are given the following information:

m_{1}=12000kg\\v_{1}=2\frac{m}{s}\\m_{2}=10000kg\\v_{2}=0\frac{m}{s}(at rest)

So, substituting and calculating, we have:

m_{1}v{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{f}\\\\12000kg*2\frac{m}{s}+10000kg*0\frac{m}{s}=(12000kg+10000kg)*v_{f}\\\\v_{f}=\frac{24000\frac{kg.m}{s} }{22000kg}=1.09m\frac{m}{s}

Hence, the final speed is 1.09 m/s.

Have a nice day!

5 0
3 years ago
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