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Lady bird [3.3K]

2 years ago

15

THE ONE WHO WILL ANSWER IT CORRECT WILL BE MARKED AS "BRAINLIST"....... If the radius of the orbit of a spaceship from the centr

e of the earth is twice the radius of the earth . then calculate the acceleration due to the gravity on space ship.

1 answer:

jonny [76]2 years ago

5 0

Answer:

Explanation:

19116 being the distance from the centre of the earth to the point you want to check in metres. So after all that you get G = 1.0888m/second squared. Hope that helps you/ you should be able to pop in any height you want.

plz mark as brainliest

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3. A net force of 15 N acts upon a body of

denis23 [38]

Answer:

25 m/s

Explanation:

F=ma

15 N =(3 kg)a

a = 5 m/s^2

change in velocity = a*t = (5 m/s^2) * (5 secs) = 25 m/s

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3 years ago

I need this question answered about the solar system.

blsea [12.9K]

Answer:

Explanation the third one for the second question

4 0

2 years ago

A common carnival ride, called a gravitron, is a large r = 11 m cylinder in which people stand against the outer wall. the cylin

Leya [2.2K]

Answer:

v = 13.19 m / s

Explanation:

This problem must be solved using Newton's second law, we create a reference system where the x-axis is perpendicular to the cylinder and the Y-axis is vertical

X axis

N = m a

Centripetal acceleration is

a = v² / r

Y Axis

fr -W = 0

fr = W

The force of friction is

fr = μ N

Let's calculate

μ (m v² / r) = mg

μ v² / r = g

v² = g r / μ

v = √ (g r /μ)

v = √ (9.8 11 / 0.62)

v = 13.19 m / s

7 0

2 years ago

I will thank and give 5 stars to whoever answers!!

uranmaximum [27]

Answer:

1.moon

2.Earth is the first planet with a satellite, or moon.

3.Mars, the fourth planet out, has two moons, but they are probably just a couple of big old rocks.

5.The incoming object was destroyed on impact, reduced to vapor, dust, and chunks. Large surviving parts were driven deep into the interior of Earth. A signicant portion of Earth was destroyed as well. The energy that resulted from the crash produced an explosion of unimaginable magnitude.

Explanation:

i did what i can

7 0

2 years ago

Read 2 more answers

A Christmas light is made to flash via the discharge of a capacitor. The effective duration of the flash is 0.25 s (which you ca

Sonbull [250]

Answer:

The correct solution is:

(a) $1.375\times 10^{-2} \ J$

(b) $4.43\times 10^{-3} \ C$

(c) $1.42\times 10^{-3} \ F$

(d) $178.57 \ \Omega$

Explanation:

The given values are:

Effective duration of the flash,

ζ = 0.25 s

Average power,

$P_{avg}=55 \ mW$

$=55\times 10^{-3} \ W$

Average voltage,

$V_{avg}=3.1 \ V$

Now,

(a)

⇒ $E=P_{avg}\times \zeta$

On substituting the values, we get

⇒ $=55\times 10^{-3}\times 0.25$

⇒ $=1.375\times 10^{-2} \ J$

(b)

⇒ $E=Q\times V_{avg}$

then,

⇒ $Q=\frac{E}{V_{avg}}$

On substituting the values, we get

⇒ $=\frac{1.375\times 10^{-2}}{3.1}$

⇒ $=4.43\times 10^{-3} \ C$

(c)

⇒ $C=\frac{Q}{V}$

⇒ $=\frac{4.43\times 10^{-3}}{3.1}$

⇒ $=1.42\times 10^{-3} \ F$

(d)

As we know,

⇒ $R=\frac{1}{4C}$

⇒ $=\frac{1}{4\times 1.42\times 10^{-3}}$

⇒ $=\frac{1000}{5.6}$

⇒ $=178.57 \ \Omega$

5 0

2 years ago