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polet [3.4K]
2 years ago
13

Like i keep saying ANSWER the best one gets brainlyest

Mathematics
1 answer:
irga5000 [103]2 years ago
3 0

Answer:

Jazz and opera

Step-by-step explanation:

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Use only an associative property to rewrite the following expression.<br> (pk)•r=
Gennadij [26K]

Answer:

Step-by-step explanation:

(pk) * r = p * (kr)

5 0
3 years ago
SOMEONE HELP ME FIND THE Y PLEASE ASAP
Evgesh-ka [11]

Answer:

(Down Below)

Step-by-step explanation:

Plug in the value of x in the left column for all the values in the equation. I will do a couple for you.

Since -4 is the value of x, substitute it into the equation for x.

y= -4-5=-9

-1

y=-1-5=-6

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y=0-5=-5

You can do the rest. You got this! Comment if you need more help!

3 0
2 years ago
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Convert to quarts: 10 pints
Ad libitum [116K]

Answer:

B

Step-by-step explanation:

Pints and Quarts are measures of volume. The relationship between them is rather simple.

We know 2 pints = 1 Quart

The problem gives us the number of pints and we need to find the number of quarts. From the relationship, we see that "pints divided by 2 will give us quarts"

Given >> 10 pints

Hence, number of quarts would be 10/2 = 5

Hence 10 pints = 5 quarts

Answer choice B is right.

8 0
3 years ago
Find maclaurin series
Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}

The first 3 terms of the series are

\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}

which amounts to replacing the x with √x in the expansion of cos(√5 x) :

\cos\left(\sqrt{5x}\right) \approx 1 - \dfrac{5x}2 + \dfrac{25x^2}{24}

7 0
2 years ago
How can I solve for c
s2008m [1.1K]

Answer:

(\frac{2}{5})c

8 0
3 years ago
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