First 3/8, second 2/3, and third 19/24
Answer:
$5 + 2.50k ≤ $20
6 kilometers
Step-by-step explanation:
Puedes viajar con $15 porque gastaste 5 en la tarifa base. 15 dividido por 2,5 es 6, por lo que puedes viajar 6 kilómetros con $20.
Answer:
3).
4).
If it was by 10, k = 3 by 10
k = 30
5).
Step-by-step explanation:
To me yes.
Algebra is mostly memorization. If you know the formulas and know how to apply it, you should do good.
I say use this. Algebra topics are like building on top each other.
Heart of Algebra:
- Review what the purpose of x in algebra.
- Then learn things like combining like terms, and solving for x.
- Since you know the basics of x, you can then review linear equations( imo, a big content of algebra). Stuff like slope, different linear forms, graphs of linear equations, and mostly linear equation word problems
- Then you can review system of equations. since you know how to manipulate linear equations, etc.
Then move on to other algebra topics dealing with algebra like
- functions, and different types of them
- exponents, and radicals rules
- inequalities.
- sequences.
- These aren't the heart of algebra but study them they are useful and it important to know them.
Since you learned different function rules, we can move on to learning exponetial functions, graphs, and word problems.
Then finally, learn most hard thing in Algebra: Quadratics.
Pratice,practice, and practice and you will pass.
Try to memorize the formulas and know when to apply it.
Good Luck
Answer:
True
Step-by-step explanation:
In order for a relation (a set of ordered pairs) to be considered a <em>function</em>, every value in the <em>domain</em> (the set of all the first numbers in the pair) is associated with one value in the <em>range</em> (the set of all second numbers in the pair). This is easiest to see visually. Our domain is the set {2, 3, 4, 5} and our range is the set {4, 6, 8, 10}, and we can visualize the ordered pair (2, 4) as an "arrow" starting a 2 in the domain and ending at 4 in the range. When seen this way, a relation is a function if <em>every value in the domain only has one arrow coming out of it</em>. We can see from the attached picture that the ordered pairs in the problem are a function, so this statement is true.
