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s2008m [1.1K]
2 years ago
12

you are heating a solution and recording its temperature every 2 min during an experiment. which is your independent variable an

d which is your dependent variable
Chemistry
1 answer:
Zepler [3.9K]2 years ago
7 0
An independent variable is the variable you are changing in order to measure the dependent variable, which is what you are measuring.

In this example, the

independent variable: chemicals in solution
dependent variable: temperature of solution
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What does the red represent on the model? *
kaheart [24]
The red is an oxygen molecule. 1 oxygen and 2 hydrogen =h2o or water!
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2 years ago
Free-energy change, ΔG∘, is related to cell potential, E∘, by the equation ΔG∘=−nFE∘ where n is the number of moles of electrons
elena-s [515]

Answer:

-372000 J or -372 KJ

Explanation:

We have the electrochemical reaction as;

Mg(s)  +  Fe^2+(aq)→  Mg^2+(aq)  +   Fe(s)

We must first calculate the E∘cell from;

E∘cathode -  E∘anode

E∘cathode = -0.44 V

E∘anode = -2.37 V

Hence;

E∘cell = -0.44 V -(-2.37 V)

E∘cell = 1.93 V

n= 2 since two electrons were transferred

F=96,500C/(mol e−)

ΔG∘=−nFE∘

ΔG∘= -( 2 * 96,500 * 1.93)

ΔG∘= -372000 J or -372 KJ

4 0
2 years ago
As one mass increases, what happens to the gravitational force.
Shalnov [3]

Answer:

Gravitational force is directly promotional to the mass

of both interacting objects.

Explanation:

More massive objects will attract each other with

a greater gravitional force. So as the mass of the

either objects increases the force of gravitational

attraction between them also increases.

8 0
2 years ago
What are the reactants and products when butane combusts with excess oxygen? express your answer as a chemical equation. the equ
Vikki [24]
C4H10 + O2 -----> CO2 +H2O
5 0
3 years ago
It takes 60 mL of 0.20 M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H2CO3) for the following chemical reac
irina1246 [14]

If It takes 60mL of 0.20M of sodium hydroxide (NaOH) to neutralize 25 mL of carbonic acid (H_2CO_3), then the concentration of the carbonic acid is 0.24M

The reaction between NaOH solution and H_2CO_3 is written below

2NaOH + H_2CO_3 \rightarrow Na_2CO_3 + 2H_2O

Volume of NaOH, V_B = 60 ml

Volume of H_2CO_3, V_A=25 ml

Molarity of H_2CO_3, C_A=?

Molarity of NaOH, C_B=0.20M

Number of moles of H_2CO_3, n_A=1

Number of moles of NaOH, n_B=2

The mathematical equation for neutralization reaction is:

\frac{C_AV_A}{C_BV_B} =\frac{n_A}{n_B}

Substitute  C_B=0.2 M,  n_A=1,  n_B=2,  V_B = 60ml, and  V_A=25 ml into the equation above in order to solve for C_A

\frac{C_A \times 25}{0.2 \times 60}=\frac{1}{2}  \\\\50C_A=12\\\\C_B=\frac{12}{50} \\\\C_B=0.24M

Therefore, the concentration of the carbonic acid is 0.24M

Learn more here: brainly.com/question/25943090

3 0
1 year ago
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