Answer:
111.15 g are required to prepare 500 ml of a 3 M solution
Explanation:
In a 3 M solution of Ca(OH)₂ there are 3 moles of Ca(OH)₂ per liter solution. In 500 ml of this solution, there will be (3 mol/2) 1.5 mol Ca(OH)₂.
Since 1 mol of Ca(OH)₂ has a mass of 74.1 g, 1.5 mol will have a mass of
(1.5 mol Ca(OH)₂ *(74.1 g / 1 mol)) 111.15 g. This mass of Ca(OH)₂ is required to prepare the 500 ml 3 M solution.
Answer:
MgO.
Explanation:
charges of both satisfy one another (balanced) -- producing a compound MgO.
Based on the information given, it should be noted that the ground-state electron configuration of carbon is 1s2 2s2 2p2.
<h3>
What is an electron?</h3>
Electrons are simply the subatomic particles which orbit the nucleus of an atom.
The arrangement of electrons in the atomic orbitals of an atom is known as the electron configuration. This can be determined by using a periodic table.
It should be noted that carbon is the sixth element with a total of 6 electrons in the periodic table. Thus, the atomic number Z = 6.
In conclusion, the ground-state electron configuration of carbon is 1s2 2s2 2p2.
Learn more about carbon on:
brainly.com/question/105003
Answer:
M₂ = 0.0745 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.0952 M
V₁ = 38.73 mL
M₂ = ?
V₂ = 49.48 mL
Using the above formula , the molarity of ammonia , can be calculated as ,
M₁V₁ = M₂V₂
0.0952 M * 38.73 mL = M₂* 49.48 mL
M₂ = 0.0745 M
Answer:
P = 0.6815 atm
Explanation:
Pressure = 754 torr
The conversion of P(torr) to P(atm) is shown below:
So,
Pressure = 754 / 760 atm = 0.9921 atm
Temperature = 294 K
Volume = 3.1 L
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
0.9921 atm × 3.1 L = n × 0.0821 L.atm/K.mol × 294 K
⇒n of helium gas= 0.1274 moles
Surface are = 1257 cm²
For a sphere, Surface area = 4 × π × r² = 1257 cm²
r² = 1257 / 4 × π ≅ 100 cm²
r = 10 cm
The volume of the sphere is :
Where, V is the volume
r is the radius
V = 4190.4762 cm³
1 cm³ = 0.001 L
So, V (max) = 4.19 L
T = 273 K
n = 0.1274 moles
Using ideal gas equation as:
PV=nRT
Applying the equation as:
P × 4.19 L = 0.1274 × 0.0821 L.atm/K.mol × 273 K
<u>P = 0.6815 atm</u>
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