Answer:
SDFK fbsdfasdgasdfgasdfg⊃⊃⊃⊃⊃⊃×∈⇔⇔⇔
Explanation:
Answer:
No, the farmer is not able to move the mule.
Explanation:
Mass =100 kg
Force=F=800 N
The coefficient between the mule and the ground=

Static friction force,f=
Normal force=N=mg
Static friction force,f=
Using 
F<f
Static friction force is greater than applied force.
Therefore , the farmer is not able to move the mule.
Yes u can help I need to see th worksheet to help tho
Answer:

Explanation:
From the question we are told that:
Mass 
Charge 
Velocity 
Length of Wire 
Current 
Generally the equation for Magnetic Field of Wire B is mathematically given by



Generally the equation for Force on the plane F is mathematically given by

Therefore




Therefore in Terms of g's

