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goldfiish [28.3K]
3 years ago
10

Define kinetic energy in your own words, and write a statement about how kinetic energy is affected as velocity increases.

Physics
1 answer:
ANEK [815]3 years ago
3 0
<h2>Sentence:</h2><h3><u><em>When something is in motion, it has kinetic energy. Wind and water are examples of things with kinetic energy because they are moving. Electricity is also a form of kinetic energy.</em></u></h3>

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Calculate the value of δs when 64.0 g of ga(l) solidifies at 29.8 ∘c.
frez [133]
The variation of entropy of a substance is given by
\delta S =  \frac{\delta Q}{T} (1)
where
\delta Q is the heat exchanged in the process
T is the absolute temperature at which the transformation occurs.

The process in the problem is the solidification of the liquid Gallium, which releases an amount of heat equal to:
\delta Q = m L_f
where m is the mass of the substance and L_f = 80.1 J/g is the latent heat of fusion of Gallium. Using m=64.0 g, we find
\delta Q= m L_f = (64.0 g)(80.1 J/g)=-5126.4 J
where the negative sign means the Gallium is releasing heat to the environment.

Now we can use equation (1) to find the variation of entropy, but first we need to convert the temperature into Kelvin:
T=29.8^{\circ} + 273.15 = 302.95 K

And so the variation of entropy is 
\delta S =  \frac{\delta Q}{T}= \frac{-5126.4 J}{302.95 K}=-16.92 J
and the negative sign means the entropy in the process is decreasing.

7 0
4 years ago
Calculate the coefficient of friction of a 12kg object that has a force of friction of 3N
postnew [5]

Answer:

0.026

Explanation:

The force of friction acts in the direction perpendicular to the norm force of the surface on which the object rests, induced by gravity. The magnitude of the friction force is

(Friction) = (mass) x (gravitational acceleration g) x (coefficient of friction)

from which the coefficient of friction can be determined:

(coefficient of friction) = (Friction) / ((mass)x(g)) = 3 N / (12 kg * 9.8 m/s^2) = 0.026

3 0
3 years ago
I drop an egg from a certain distance and it takes the egg 3.74 seconds to reach the ground. How high up was the egg?
Slav-nsk [51]

Answer:

The height from which the egg is dropped is <u>68.54 m</u>.

Explanation:

Given:

Initial velocity of egg is, u=0\ m/s(Dropped means initial velocity is 0)

Time taken is, t=3.74\ s

Acceleration experienced by egg is due to gravity, a=g=9.8\ m/s^2

The height from which the egg is dropped is, d=?

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

d=ut+\frac{1}{2}at^2

Plug in all the given values and solve for 'd'. This gives,

d=0+\frac{1}{2}\times 9.8\times (3.74)^2\\\\d=\frac{1\times 9.8\times 13.9876}{2}\\\\d=\frac{137.078}{2}\\\\d=68.54\ m

Therefore, the height from which the egg is dropped is 68.54 m.

8 0
3 years ago
HELP PLEASE! Need ASAP!!! Will mark brainiest
11111nata11111 [884]

Answer:

1: D-  attach the muscle to bones and allow for movement

2:A- skeletal

3. A- speaking

Explanation:

8 0
3 years ago
Read 2 more answers
In deep space (no gravity), the bolt (arrow)
salantis [7]

t  = 0.527 s

<u>It accelerates for 0.527 s.</u>

<u>Explanation:</u>

We use the formula:

v = u+at

Given:

v = 106 m/s

u = 0 (since no gravity)

a=201 \mathrm{m} / \mathrm{s}^{2}

So applying the formula,

v = u+at

106 = 0 + 201t

t     = 106/201

t     = 0.527 s

4 0
3 years ago
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