Answer:
The third drop is 0.26m
Explanation:
The drop 1 impacts at time T is given by:
T=sqrt(2h/g)
T= sqrt[(2×2.4)/9.8]
T= sqrt(4.8/9.8)
T= sqrt(0.4898)
T= 0.70seconds
4th drops starts at dT=0.70/3= 0.23seconds
The interval between the drops is 0.23seconds
Third drop will fall at t= 0.23
h=1/2gt^2
h= 1/2×9.81×(0.23)^2
h= 0.26m
I think 6.1m i’m not sure sorry if i’m wrong
If they are connected exactly as shown, nothing can happen.
Force = 3200 N
Work done = 640, 000 Nm
Explanation:
We begin by calculating the deceleration of the truck, using the velocity and distance;
a = (v² – u²)/2s
whereby;
a = acceleration
v = initial velocity
u = initial velocity
s = distance
We begin by changing the speed from km/h into m/s;
54km/hr = 15m/s
Then acceleration;
a = (0² – 15²) / 2 * 200
a = -225 / 400
a = - 0.5625 m/ s²
To calculate force;
F = ma
Whereby;
F = force
M = mass (in kgs)
a = acceleration
F = 1800 / 0.5625
F = 3200 N
Work done = Force * displacement
Work done = 3200 * 200
= 640, 000 Nm
Learn More:
For more on force and work done check out;
brainly.com/question/8662583
brainly.com/question/1268612
brainly.com/question/11870590
brainly.com/question/9125094
#LearnWithBrainly
