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2 years ago

If the forces on an object are greater than zero, the motion of an object will what?

1 answer:

3 0

If the forces on an object are greater than zero,the object will definitely in the motion. This concept in accordance with law of inertia.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Newton's law of inertia states that a body wants to continue its motion until the external force is not acted on it.

Hence, if the force is grater than zero, the body will be in motion.

To learn more about the force, refer to the link;

brainly.com/question/26115859

#SPJ1

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a child goes down the slide, starting from rest. if the length of the slide is 2m and it takes the child 3 seconds to go down th

Doss [256]

nvm deleting.................................

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4 years ago

A runner begins from rest at the starting line and travles for 6.5 seconds, a runner reaches a speed of 13.4 m/s what is the run

Butoxors [25]

The acceleration of the runner in the given time is 2.06m/s².

Given the data in the question;

Since the runner begins from rest,

Initial velocity; $u = 0$

Final velocity; $v = 13.4m/s$

Time elapsed; $t = 6.5s$

Acceleration of the runner; $a = \ ?$

<h3>Velocity and Acceleration</h3>

Velocity is the speed at which an object moves in a particular direction.

Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion

$v = u + at$

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

To determine the acceleration of the runner, we substitute our given values into the equation above.

$v = u + at\\\\13.4m/s = 0 + (a * 6.5s)\\\\13.4m/s = a * 6.5s\\\\a = \frac{13.4m/s}{6.5s}\\ \\a = 2.06m/s^2$

Therefore, the acceleration of the runner in the given time is 2.06m/s².

Learn more about Equations of Motion: brainly.com/question/18486505

3 0

2 years ago

What type of structure is the cytoplasm? I Will mark as brainiest if right

Irina-Kira [14]

145,600 it equals 145,600 so you put down the zeros

4 0

3 years ago

Starting from rest, a crate of mass m is pushed up a frictionless slope of angle theta by a horizontal force of magnitude F. Use

ludmilkaskok [199]

Answer:

v = sqrt[2*(F*h*cot(theta)-mgh)/m]

Explanation:

Work = KE + Ug

F*r=1/2mv^2+mgh

1/2mv^2=F*r-mgh

v=sqrt[2(F*r-mgh)/m]

r=h/tan(theta)=h*cot(theta)

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3 years ago

How do we get this equation ??<br><br><br> H=V^2÷R

lesantik [10]

$H=\frac{V^2}{R}\times t$ is the equation that represents the Joule's law of heating.

<h3>Explanation:</h3>

Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to

1. Square of Current (I²),

2. Resistance of the conductor (R)

3. Time for which current is passed (t)

Hence, Heat generated = $H = I^2 Rt$ .....................(1)

By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).

$V\ \alpha\ I\\V=I\times R$ ...............................................(2)

From (2), Current (I) can be rewritten as

$I = \frac{V}{R}$ ........................................................(3)

Substituting (3) in (1), we get

$H = I^2\times R\times t \\=(\frac{V}{R} )^2\times R\times t\\\\=\frac{V^2}{R^2}\times R\times t = \frac{V^2}{R}\times t\\\\ H =\frac{V^2}{R}\times t$

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3 years ago