The acceleration of the runner in the given time is 2.06m/s².
Given the data in the question;
Since the runner begins from rest,
- Initial velocity;  
- Final velocity;  
- Time elapsed;  
Acceleration of the runner; 
<h3>Velocity and Acceleration</h3>
Velocity is the speed at which an object moves in a particular direction.
Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.
To determine the acceleration of the runner, we substitute our given values into the equation above.

Therefore, the acceleration of the runner in the given time is 2.06m/s².
Learn more about Equations of Motion: brainly.com/question/18486505
 
        
             
        
        
        
145,600 it equals 145,600 so you put down the zeros
        
             
        
        
        
Answer:
v =  sqrt[2*(F*h*cot(theta)-mgh)/m]
Explanation:
Work  = KE + Ug
F*r=1/2mv^2+mgh
1/2mv^2=F*r-mgh
v=sqrt[2(F*r-mgh)/m]
r=h/tan(theta)=h*cot(theta)
 
        
             
        
        
        
 is the equation that represents the Joule's law of heating.
 is the equation that represents the Joule's law of heating.
<h3>
Explanation:</h3>
Joule's law of heating defines the heat generated by any current flowing conductor is directly proportional to  
1. Square of Current (I²),
2. Resistance of the conductor (R)
3. Time for which current is passed (t)
Hence, Heat generated =  .....................(1)
 .....................(1)
By Ohm's Law, the potential difference (V) across a conductor is directly proportional to the current(I) flowing through it. The constant of proportionality is termed as resistance of the conductor (R).
 ...............................................(2)
 ...............................................(2)
From (2), Current (I) can be rewritten as 
 ........................................................(3)
 ........................................................(3)
Substituting (3) in (1), we get
