18°C = _____ -255 K 0 K 18 K 291 K
2 answers:
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Answer:
62.06 g/mol
Explanation:
We are given that a solution containing 10 g of an unknown liquid and 90 g
Given mass of solute ==10 g
Given mass of solvent==90 g
Freezing point of solution =-3.33C
Freezing point of solvent =C
Change in freezing point =Depression in freezing point
=Freezing point of solvent - freezing point of solution=0+3.33=
Hence, molar mass of unknown liquid is 62.06g/mol.
Answer:
n the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
Explanation:
Velocity is a vector therefore it has magnitude and direction, a change in either of the two is the consequence of an acceleration on the system.
In the case of linear motion, the change occurs in the magnitude of the velocity, the direction remaining constant.
= (v₂-v₁)/Δt
In the case of circular motion, the magnitude of the velocity remains constant, the change in its direction occurring.
= v2/R
In the general case, both the module and the address change
a = Ra ( a_{t}^2 + a_{c}^2)