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NNADVOKAT [17]
2 years ago
5

What is the difference between accurate data and reproducible data?

Chemistry
1 answer:
Mkey [24]2 years ago
8 0

Answer:

HERE IS UR ANSWER...

The data which is accurate means it can't be changed further is called accurate data.while,

The data which is changed again and again is called reproducible data.

HOPE IT'S HELP U..

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What is an easy way to measure the volume of an irregular shaped object?
pickupchik [31]

Answer: Water displacement

Explanation:

When you put an irregularly shaped object in a graduated cylinder, the water level rises. Subtract the original number of ml from the number of ml it was displaced, and you get its volume.

4 0
2 years ago
Liquid nitrogen is cold and can be used to cool objects to -196°C. If you put the bottle of warm air in liquid nitrogen at this
vampirchik [111]

Answer:

Explanation:

It depends on how this is done. If you raise the pressure, the nitrogen will disappear (liquify) and all that will be left will be the 21 % oxygen and the 1% argon.

The process is very complicated because the boiling point of nitrogen keeps on changing. The boiling point is unstable.

6 0
2 years ago
Basically everything is in the picture, and i dont really understand please help.
zubka84 [21]
This is what I found

5 0
3 years ago
A 80.0 g piece of metal at 88.0°C is placed in 125 g of water at 20.0°C contained in a calorimeter. The metal and water come to
grandymaker [24]

Answer:

The specific heat of the metal is 0.485 J/g°C

Explanation:

<u>Step 1:</u> Data given

Mass of the piece of metal = 80.0 grams

Mass of the water = 125 grams

Initial temperature of the metal = 88.0 °C

Initial temperature of water =20.0 °C

Final temperature = 24.7 °C

pecific heat of water is 4.18 J/g*°C

<u>Step 2:</u> Calculate specific heat of the metal

Qgained = -Qlost

Q =m*c*ΔT

Qwater = - Qmetal

m(water)*c(water)*ΔT(water) = -m(metal)*c(metal)*ΔT(metal)

with mass of water = 125 grams

with c( water) = 4.18 J/g°C

with ΔT(water) = T2-T1 = 24.7 - 20 = 4.7°C

with mass of metal = 80.0 grams

with c(metal) = TO BE DETERMINED

with ΔT(metal) = 24.7 - 88.0 = -63.3 °C

125*4.18*4.7 = -80 * C(metal) * -63.3

2455.75 = -80 * C(metal) * -63.3

C(metal) = 2455.75 / (-80*-63.3)

C(metal) = 0.485 J/g°C

The specific heat of the metal is 0.485 J/g°C

3 0
3 years ago
I need help ASAP!!!!!!!!!!!!!!!!!!!
liraira [26]

last one? don't take my word though

Explanation:

the suns heat is related to nuclear fusion

6 0
2 years ago
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