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NNADVOKAT [17]
2 years ago
5

What is the difference between accurate data and reproducible data?

Chemistry
1 answer:
Mkey [24]2 years ago
8 0

Answer:

HERE IS UR ANSWER...

The data which is accurate means it can't be changed further is called accurate data.while,

The data which is changed again and again is called reproducible data.

HOPE IT'S HELP U..

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Structure for reductive ozonolysis of 3,5-dimethyl-4-octene​
brilliants [131]

Answer:

Scheme is Attached.

When 3,5 dimethyl-4- octene is react with ozone two products are obtain.

2-Methyl butanal and 2 pentanon.

The complete reaction is given in attached file.

3 0
3 years ago
Which 5.0-milliliter sample of NH3 will take the shape of and completely fill a closed 100.0-milliliter container?(1) NH3(s) (3)
antoniya [11.8K]
NH3(g) will take the shape of and completely fill a closed 100.0 milliliter container. 
5 0
3 years ago
Find the volume of a gas at STP, if its volume is 80.0 mL at 109 kPa and -12.5°C.​
exis [7]

Answer:

= 913.84 mL

Explanation:

Using the combined gas laws

P1V1/T1 = P2V2/T2

At standard temperature and pressure. the pressure is 10 kPa, while the temperature is 273 K.

V1 = 80.0 mL

P1 = 109 kPa

T1 = -12.5 + 273 = 260.5 K

P2 = 10 kPa

V2 = ?

T2 = 273 K

Therefore;

V2 = P1V1T2/P2T1

     = (109 kPa × 80 mL × 273 K)/(10 kPa× 260.5 K)

     <u>= 913.84 mL</u>

5 0
3 years ago
Read 2 more answers
May someone assist, please...? I don't know how to do chemistry work...
EastWind [94]

Answer:

1) 90.0 mL

2) 11.25 M

3) 0.477 M

4) 144 mL

Explanation:

The main formula that will be used for all these calculations is:

                                                     C₁V₁ = C₂V₂

C stands for concentration and V stands for volume and the subscripts 1 and 2 indicate an initial concentration or volume and a final concentration or volume.

For each problem, it's best to start by figuring out what you have and what you need to find. Figure out if you're looking for an initial value or a final value.

1) We need to find the initial volume. So, take what values you have and plug them in and then solve for whatever variable:

5.00 M · V₁ = 500.0mL · 0.900 M                        - divide by 5.00

C₁ = 90.0 mL

2) This time we're finding the initial concentration:

20.0mL · C₁ = 150.0mL · 1.50 M                          - divide by 20.0mL

C₂ = 11.25 M

3) Now we're finding the final concentration:

12.00mL · 3.50 M = 88.0mL · C₂                         - divide by 88.0mL

C₂ = 0.477 M

4) Finally, we're looking for the final volume:

9.0mL · 8.0 M = 0.50 M · V₂                                - divide by 0.50 M

V₂ = 144mL

6 0
3 years ago
In what situations are van der waals forces the most significant
viktelen [127]
Its most significant when all other forces are absent
7 0
3 years ago
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