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Katena32 [7]
3 years ago
9

A baseball is moving at a speed of 2.2\,\dfrac{\text{m}}{\text{s}}2.2 s m ​ 2, point, 2, space, start fraction, m, divided by, s

, end fraction when it strikes the catcher's glove. The padding of the glove is compressed by 2.4\,\text{mm}2.4mm2, point, 4, space, m, m before the ball comes to a stop. We want to find the average acceleration of the baseball while it is compressing the glove.
Physics
1 answer:
Reika [66]3 years ago
5 0

Answer:

 a = 1,008 10⁻³ m / s²

Explanation:

For this exercise, let's use the kinematic relations of accelerated motion

           v² = v₀² - 2 a x

The negative sign is because the acceleration is opposite to the speed, the final speed is zero

          0 = v₀² - 2 a x

          a = v₀² / 2x

   Let's reduce the magnitudes to the SI system

          x = 2.4mm (1m / 10³mm) = 2.4 10⁻³m

Let's calculate

         a = 2.2²/2 2.4 10⁻³

        a = 1,008 10⁻³ m / s²

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A car of mass 1500 kg is negotiating a flat circular curve of radius 50 m with a speed of 20 m/s.
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Answer:

Explanation:

a. The source of centripetal force on the car is  (3) the static friction force.

b. ac = v²/R = (20²)/50 = 8 m/s²

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d. μ = Fc/N = Fc/mg = 12000 / 1500(9.8) = 0.8163... ≈ 0.82

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A pet-store supply truck moves at 25.0 m/s north along a highway. inside, a dog moves at 1.75 m/s at an angle of 35.0° east of n
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3 years ago
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True or False an overtone occurs when two or more sound waves are produced at the same time.
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3 years ago
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1. An object is projected upward with a velocity of 125 m/s.
grigory [225]

Answer:

A) s = 796.38 m

B) t = 12.742 s

C) T = 25.484 s

Explanation:

A) First of all let's find the time it takes to get to maximum height using Newton's first equation of motion.

v = u + gt

u = 125 m/s

v = 0 m/s

g = 9.81 m/s²

Thus;

0 = 125 - 9.81(t)

g is negative because motion is against gravity. Thus;

9.81t = 125

t = 125/9.81

t = 12.742 s

Max height will be gotten from Newton's 2nd equation of motion;

s = ut + ½gt²

s = (125 × 12.742) + (½ × -9.81 × 12.742²)

s = 1592.75 - 796.37

s = 796.38 m

B) time to reach maximum height is;

t = u/g

t = 125/9.81

t = 12.742 s

C) Total time elapsed is;

T = 2u/g

T = 2 × 125/9.81

T = 25.484 s

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3 years ago
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