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Katena32 [7]
3 years ago
9

A baseball is moving at a speed of 2.2\,\dfrac{\text{m}}{\text{s}}2.2 s m ​ 2, point, 2, space, start fraction, m, divided by, s

, end fraction when it strikes the catcher's glove. The padding of the glove is compressed by 2.4\,\text{mm}2.4mm2, point, 4, space, m, m before the ball comes to a stop. We want to find the average acceleration of the baseball while it is compressing the glove.
Physics
1 answer:
Reika [66]3 years ago
5 0

Answer:

 a = 1,008 10⁻³ m / s²

Explanation:

For this exercise, let's use the kinematic relations of accelerated motion

           v² = v₀² - 2 a x

The negative sign is because the acceleration is opposite to the speed, the final speed is zero

          0 = v₀² - 2 a x

          a = v₀² / 2x

   Let's reduce the magnitudes to the SI system

          x = 2.4mm (1m / 10³mm) = 2.4 10⁻³m

Let's calculate

         a = 2.2²/2 2.4 10⁻³

        a = 1,008 10⁻³ m / s²

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Waves carry energy from one place to another. Because waves carry energy, some waves are used for communication, eg radio and television waves and mobile telephone signals. ... Some types of waves need to be transmitted through matter, either a solid, liquid or a gas. For example, water waves have to travel in water.
3 0
3 years ago
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What force does it take to accelerate a 7.2 kg object 3.0 m/s^2.
grin007 [14]

Answer:

<h2>21.6 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 7.2 × 3 = 21.6

We have the final answer as

<h3>21.6 N</h3>

Hope this helps you

3 0
2 years ago
A 400-kg object has a 100-Newton rightward net force being applied to it. What is the magnitude of the rightward acceleration on
aliya0001 [1]

Answer:

The answer to your question is a = 0.25 m/s²

Explanation:

Data

mass = m = 400 kg

Force = F = 100 N

acceleration = a = ? m/s²

Process

To solve this problem use Newton's second law that states that the force applied to an object is directly proportional to the mass of the body times its acceleration.

Formula

                       F = ma

solve for a

                       a = \frac{F}{m}

Substitution

                       a = \frac{100}{400}

Simplification and result

                              a = 0.25 m/s²

5 0
3 years ago
If a canadian plane is traveling at 500 miles/hr, how fast is this in m/s?
patriot [66]
223.52 meters per second
6 0
3 years ago
Water (density = 1 ´ 103 kg/m3) flows at 10 m/s through a pipe with radius 0.030 m. the pipe goes up to the second floor of the
Hatshy [7]

density of water = 1000 kg/m^3

velocity of flow = 10 m/s

radius of pipe = 0.030 m

Height of second floor = 2 m

Now we can use here Bernuoli's Equation to find the speed of water flow at second floor

P_1 + 1/2\rho v_1^2 + \rho g h_1= P_2 + 1/2 \rho v_2^2 + \rho g h_2

P + 1/2 * 1000 * 10^2 + 1000* 9.8 * 0 = P + 1/2 * 1000 * v^2 + 1000*9.8*2

v = 7.8 m/s

Now in order to find the radius of pipe we can use equation of continuity

A_1 v_1 = A_2 v_2

\pi *0.030^2 * 10 = \pi * r^2 * 7.8

r = 0.034 m

So radius of pipe at second floor is 0.034 meter

3 0
3 years ago
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