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Naddik [55]
3 years ago
8

Factor 5x^3 - 2x^2 using the GCF

Mathematics
1 answer:
Anni [7]3 years ago
5 0

Answer:

x^2(5x-2)

Step-by-step explanation:

The gcf of the whole expression is x^2. You then factor out it from the expression to get x^2(5x-2)

You might be interested in
How many ways can a person toss a coin 13 times so that the number of heads is between 7 and 10 inclusive?
maks197457 [2]

Answer:

4004

Step-by-step explanation:

The number of combinations of choosing r objects from a group of n is nCr.

So the number of ways to get 7, 8, 9, or 10 heads from 13 coin tosses is:

₁₃C₇ + ₁₃C₈ + ₁₃C₉ + ₁₃C₁₀

= 1716 + 1287 + 715 + 286

= 4004

3 0
3 years ago
If the width of a rectangle is(x + 5) cm and its perimeter is (10x + 26) cm.
zaharov [31]

Answer:

10x + 26 = 2x + 58

10x = 58-26

10x = 32

X = 3.2

I think??

3 0
3 years ago
Which of the following is a correct conversion of 50 kg
wariber [46]

Answer:

c. 50kg = 50,000g

Step-by-step explanation:

We have to solve these following rule of three to see which of the following is a correct conversion of 50kg.

a)

Each kg has 1000g

So

1kg - 1000g

50kg - xg

x = 50*1000

x = 50,000g

Conversion a) is wrong

b)

Each kg has 1000000mg

So

1kg - 1000000g

50kg - x mg

x = 50*1000000

x = 50,000,000 mg

Conversion b) is wrong

c)

In a), we have already converted 50kg to g. We have verified that 50kg = 50,000g. So c. is correct

d)

In b), we have already converrted 50kg to mg. We have verified that 50kg = 50,000,000g. So d. is wrong

4 0
3 years ago
Find the work done by force dield f(x,y)=x^2i+ye^xj on a particle that moves along parabola x=y^2+1 from(1,0) to (2,1)
NemiM [27]
Call the parabola P, parameterized by \mathbf r(y)=\langle y^2+1,y\rangle with 0\le y\le 1\rangle. Then the work done by \mathbf f(x,y) along P is

\displaystyle\int_P\mathbf f(x,y)\cdot\mathrm d\mathbf r=\int_{y=0}^{y=1}\mathbf f(x(y),y)\cdot\dfrac{\mathrm d\mathbf r(y)}{\mathrm dy}\,\mathrm dy
=\displaystyle\int_0^1\langle(y^2+1)^2,ye^{y^2+1}\rangle\cdot\langle2y,1\rangle\,\mathrm dy
=\displaystyle\int_0^1(2y^5+4y^3+2y+ye^{y^2+1})\,\mathrm dy=\frac73-\frac e2+\frac{e^2}2
8 0
4 years ago
Samantha’s rectangular gift is 10 inches. by 12 inches and is framed with a ribbon. She wants to use the same length of ribbon t
yanalaym [24]

<u>Answer:</u>

7 inches

<u>Step-by-step explanation:</u>

The dimension of the rectangular gift is 10 by 12 inches so let us find the perimeter of this rectangle.

Perimeter of rectangular gift = 2 (L+ W) = 2 (10 +12) = 44 inches

Since we are to use the same length of ribbon to wrap a circular clock so the perimeter or circumference of the clock should be no more than 44 inches.

2\pi r=44

r=\frac{44}{2\pi }

r=7.003

Therefore, the maximum radius of the circular clock is 7 inches.

7 0
3 years ago
Read 2 more answers
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