1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reil [10]
3 years ago
14

Mass = 386g volume= 30cm3

Chemistry
2 answers:
dezoksy [38]3 years ago
7 0
Can you be more specific, I think the answer is 7.1506
hodyreva [135]3 years ago
7 0
If you are trying to find density, you would divide mass by volume, which would be 12.9 (rounded to the nearest tenth place) so your final answer should be 12.9g/cm^3
You might be interested in
Please answer this I need it answered really soon thank you so much whoever answers this and I will give BRAINLIEST!!
max2010maxim [7]

Answer:

B extinction

Explanation:

as the species does not exist any more, the species is extinct, therefore making the pictured fossil of an extinct species

hope this helps

3 0
3 years ago
Read 2 more answers
How is radiant energy transformed into chemical energy?
hodyreva [135]

Answer:

Photosynthesis is the transformation of radiant energy to chemical energy. Plants take in water, carbon dioxide, and sunlight and turn them into glucose and oxygen. Called photosynthesis, one of the results of this process is that carbon dioxide is removed from the air.

Explanation:

7 0
3 years ago
Read 2 more answers
Phosgene (COCl2) is a toxic substance that forms readily from carbon monoxide and chlorine at elevated temperatures: CO(g) + Cl2
lapo4ka [179]

Answer: Concentration of CO = 0.328 M

Concentration of Cl_2 = 0.328 M

Concentration of COCl_2 = 0.532 M

Explanation:

Moles of  CO and Cl_2 = 0.430 mole

Volume of solution = 0.500 L

Initial concentration of CO and Cl_2  =\frac{moles}{volume}=\frac{0.430}{0.500}=0.860M

The given balanced equilibrium reaction is,

                            CO(g)+Cl_2(g)\rightleftharpoons COCl_2(g)

Initial conc.          0.860M     0.860M           0

At eqm. conc.    (0.860-x) M  (0.860-x) M     (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[COCl_2]}{[CO][Cl_2]}

Now put all the given values in this expression, we get :

4.95=\frac{x}{(0.860-x)^2}

By solving the term 'x', we get :

x =  0.532 M

Thus, the concentrations of CO,Cl_2\text{ and }COCl_2 at equilibrium are :

Concentration of CO = (0.860-x) M =(0.860-0.532) M = 0.328 M

Concentration of Cl_2 =  (0.860-x) M  =  (0.860-0.532) M = 0.328 M

Concentration of COCl_2 = x M = 0.532 M

3 0
3 years ago
Two characteristics used to classify igneous rocks are texture and
kykrilka [37]
<span>Two characteristics used to classify igneous rocks are texture and </span>Mineral Grains

8 0
3 years ago
Read 2 more answers
Which statement best describes what is taking place?
muminat
Therefore Chlorine is losing electrons and being oxidized. Hope it helps.

7 0
3 years ago
Read 2 more answers
Other questions:
  • Identify the spectator ions in the following molecular equation.
    13·1 answer
  • A chemical reaction is carried out in a closed container. The energy absorbed by the chemical reaction is 150 kJ.
    5·1 answer
  • Help me pleaseee i don't get it .
    8·1 answer
  • A golf ball has more mass than a tennis ball because it ____.
    14·1 answer
  • As the frequency of a wave generated by a radio transmitter is increased ,the wavelength
    7·1 answer
  • If you heat a liquid and measure the temperature at which it vaporizes (or boils) you are measuring...
    7·1 answer
  • How many molecules OF2 would have a mass of .132 g
    5·1 answer
  • CaF2 + (NH4)2O --&gt; 2 NH4F + CaO How many grams of NH4F can be formed from 34.6 grams of CaF2? (AKS 4f)
    15·1 answer
  • Write the advantages of modern periodic table write as more as you can and don't copy the same thing​
    14·1 answer
  • What health benefits can you get from consuming fiber? (select all that apply.)
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!