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Fofino [41]
3 years ago
7

What is the area of the composite figure? Please answer need the answer now!

Mathematics
2 answers:
allochka39001 [22]3 years ago
4 0
I think it’s 65 for this question
ludmilkaskok [199]3 years ago
3 0

Answer:

65

Step-by-step explanation:

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7x + 2y + 5 - 5x + Oy - 1<br> Simplify expresson
frozen [14]

Answer:

To do this you have to combine like terms. For example, 7x and -5x.

3 0
4 years ago
Suppose that 40 percent of the drivers stopped at State Police checkpoints in Storrs on Spring Weekend show evidence of driving
lesantik [10]

Answer:

a) 0.778

b) 0.9222

c) 0.6826

d) 0.3174

e) 2 drivers

Step-by-step explanation:

Given:

Sample size, n = 5

P = 40% = 0.4

a) Probability that none of the drivers shows evidence of intoxication.

P(x=0) = ^nC_x P^x (1-P)^n^-^x

P(x=0) = ^5C_0  (0.4)^0 (1-0.4)^5^-^0

P(x=0) = ^5C_0 (0.4)^0 (0.60)^5

P(x=0) = 0.778

b) Probability that at least one of the drivers shows evidence of intoxication would be:

P(X ≥ 1) = 1 - P(X < 1)

= 1 - P(X = 0)

= 1 - ^5C_0 (0.4)^0 * (0.6)^5

= 1 - 0.0778

= 0.9222

c) The probability that at most two of the drivers show evidence of intoxication.

P(x≤2) = P(X = 0) + P(X = 1) + P(X = 2)

^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2  (0.4)^2  (0.6)^3

= 0.6826

d) Probability that more than two of the drivers show evidence of intoxication.

P(x>2) = 1 - P(X ≤ 2)

= 1 - [^5C_0  (0.4)^0  (0.6)^5 + ^5C_1  (0.4)^1  (0.6)^4 + ^5C_2 * (0.4)^2  (0.6)^3]

= 1 - 0.6826

= 0.3174

e) Expected number of intoxicated drivers.

To find this, use:

Sample size multiplied by sample proportion

n * p

= 5 * 0.40

= 2

Expected number of intoxicated drivers would be 2

7 0
3 years ago
Helpppp pleaseeeeeeee
Katena32 [7]
The answer is B) multiply 3 by 3. With that 2 on top, that doesn't mean 3 times 2, that means multiply 3 by itself, however many times the number says, if that makes sense. So if there's a 2 above the 3, then that would be 3*3. If it was a 5 instead of a two, that would mean 3*3*3*3*3. Not 3*5.
3 0
3 years ago
If John's car gets an average of 18 mpg and he fills his tank with 26.7 gallons of gas, how far can John travel on a tank of gas
Allisa [31]
480.6 miles


multiply 18 by 26.7 to get that answer
5 0
4 years ago
Read 2 more answers
Please help ·ω· pppppppllllllllllllllleeeeeeeeeeaaaaaaaassssssssseeeeeeeeee????
AnnZ [28]

Answer:

x=49

Step-by-step explanation:

3 0
3 years ago
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