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ludmilkaskok [199]
3 years ago
9

Why does a red object appear red?

Chemistry
2 answers:
NeTakaya3 years ago
8 0

Answer:

Objects appear different colours because they absorb some colours (wavelengths) and reflected or transmit other colours. ... For example, a red shirt looks red because the dye molecules in the fabric have absorbed the wavelengths of light from the violet/blue end of the spectrum

maw [93]3 years ago
8 0

Answer:c

Explanation:

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When the following oxidation–reduction reaction in acidic solution is balanced, what is the lowest whole-number coefficient for
ruslelena [56]

Answer:

b. 16, reactant side

Explanation:

Let's consider the following redox reaction.

MnO₄⁻(aq) + I⁻(aq) → Mn²⁺(aq) + I₂(s)

We can balance it using the ion-electron method.

Step 1: Identify both half-reactions

Reduction: MnO₄⁻(aq) → Mn²⁺(aq)

Oxidation: I⁻(aq) → I₂(s)

Step 2: Perform the mass balance, adding H⁺(aq) and H₂O(l) where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) → Mn²⁺(aq) + 4 H₂O(l)

2 I⁻(aq) → I₂(s)

Step 3: Perform the charge balance, adding electrons where appropriate

MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l)

2 I⁻(aq) → I₂(s)  + 2 e⁻

Step 4: Multiply both half-reactions by numbers so that the number of electrons gained and lost are equal

2 × (MnO₄⁻(aq) + 8 H⁺(aq) + 5 e⁻ → Mn²⁺(aq) + 4 H₂O(l))

5 × (2 I⁻(aq) → I₂(s)  + 2 e⁻)

Step 5: Add both half-reactions and cancel what is repeated on both sides

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 e⁻ + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)  + 10 e⁻

The balanced reaction is:

2 MnO₄⁻(aq) + 16 H⁺(aq) + 10 I⁻(aq) → 2 Mn²⁺(aq) + 8 H₂O(l) + 5 I₂(s)

5 0
2 years ago
Does water evaporate ant any temprature
natka813 [3]

Answer:

No

Explanation:

I'm not educated enough on the matter but from what I've been taught water boils at 100 Celsius and it simultaneously evaporates.

6 0
2 years ago
Need help for number 4. do i use the q=mc DELTA T equation or the q=mHfusion?
Natasha2012 [34]
Since it is a phase change, use the mHfusion equation.
7 0
3 years ago
A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som
Andrews [41]

The given question is incomplete. The complete question is as follows.

A certain liquid has a normal boiling point of 124.2^{o}C and a boiling point elevation constant k_{b} = 0.62 ^{o}C kg mol^{-1}. A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at 127.4^{o}C. Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.

Explanation:

As per the colligative property, the elevation in boiling point will be as follows.

     

T = boiling point of the solution =

T_{o} = boiling point of the pure solvent = 124.2^{o}C

K_{b} = elevation of boiling constant = 0.62 ^{o}C kg mol^{-1}

We will calculate the molality as follows.

     molality = \frac{\text{maas of solute}}{\text{molar mass of solute}} \times \frac{1000}{\text{mass of solvent in g}}

i = vant hoff's factor

As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.

Putting the given values into the above formula as follows.  

    T - T_{o} = i \times K_{b} \times \text{molality of solution}

  (127.4 - 124.2)^{o}C = 2 \times 0.62 \times \frac{m}{60} \times \frac{1000}{650}

                  m = 100 g

Therefore, we can conclude that 100 g of NaCl was dissolved.

3 0
3 years ago
Please Heeelp!!
Sliva [168]

2 HClO(aq) + Ca(OH)2(aq) = 2 H2O(l) + Ca(ClO)2(aq) is the balanced equation

4 0
2 years ago
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