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arsen [322]
3 years ago
6

A representation of a chemical reaction that uses symbols to show the relationship between the reactants and the products is cal

led a __________.
a.
symbolic statement
b.
chemical equation
c.
mole ratio
d.
chemical proportion


Please select the best answer from the choices provided
Physics
2 answers:
VARVARA [1.3K]3 years ago
8 0

Answer:

(B) chemical equation

Explanation:

Chemical equation is a representation of how reactant form products using chemical symbols.

The reactant are usually in the left hand side of the equation, while the products are kept at the right hand side of the equation. A long arrow is placed in-between them to indicate the direction of the reaction. Some chemical reactions requires number to balance the amount of reactant and products in the equation since law of conservation of matter must be strictly adhered to. Eg

NaOH + HCl ———》 NaCl + H2O

mezya [45]3 years ago
5 0

Answer:

a.

it's a symbolic statement. as it shows only sybols

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Answer:

0.053 rad/s^2

Explanation:

0.2 rev/s = 0.2 rev/s * 2π rad/rev = 0.4π rad/s

Since the angular acceleration is assumed to be constant, and the wheel's angular speed is increasing from rest (0 rad/s) to 0.4π rad/s within 23.8s. Then the angular acceleration must be

\alpha = \Delta \omega / \Delta t = \frac{0.4 \pi - 0}{23.8} = 0.053 rad/s^2

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Which graph represents the relationship between the magnitude of the gravitational force exerted by earth on a spacecraft the di
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Answer:

B as distance increase force decrease, but it is not a linear relationship.

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Explain why it may make more sense to colonize on Venus, rather than Mars.
SVEN [57.7K]

Venus is closer, relatively the same size as the earth and has an atmosphere

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3 years ago
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What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.
valkas [14]
<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period T of a body (moon, planet, satellite) orbiting a greater body in space with the size a of its orbit.

This Law is originally expressed as follows:

T^{2}=\frac{4\pi^{2}}{GM}a^{3}   (1)

Where;

G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

M=6.39(10)^{23}kg is the mass of Mars

a=3.4(10)^{6}m  is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}    (2)

T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}    (3)

T=\sqrt{11581157.44 s^{2}}    (4)

Finally:

T=3403.1099s=56.718min    This is the orbital period of a spacecraft in a low orbit near the surface of mars

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the rifle exerts same force in opposite direction so we have

11.05 = 3.5 * a
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