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matrenka [14]
3 years ago
5

According to Coulomb's law, when the distance between two point charges doubles, what happens to the electric force acting betwe

en the charges?
Physics
1 answer:
Dafna11 [192]3 years ago
3 0

Answer:

If the distance between charges is doubled, then the Force will become one-fourth.

F' = F/4

Explanation:

The Coulomb's Law gives the relation for the attractive or repulsive forces between two charges. The relation or formula is given as follows:

F = kq₁q₂/r²

where,

F = Attractive or Repulsive forces between the charges

k = Coulomb's Constant

q₁ = magnitude of 1st charge

q₂ = magnitude of 2nd charge

r = distance between charges

If we keep the magnitude of charges constant then the relation between Force an Distance between charges will be:

F α 1/r²

<u>So, it is clear from this relation that if the distance between charges is doubled, then the Force will become one-fourth.</u>

<u>F' = F/4</u>

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There are different life examples of convection.

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3 years ago
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A chamber fitted with a piston contains 1.90 mol of an ideal gas. Part A The piston is slowly moved to decrease the chamber volu
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Answer:

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Using formula of work done

W=nRT\ ln(\dfrac{V_{f}}{V_{i}})

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3 years ago
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Answer:

Explanation:

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t = 2×4×sin 60 / 9.8

t = 0.71 seconds

2) Distance where it hit the ground is called as range and has the following standard equation

D = v² sin2Ф/g

D = 4²sin 2×60 / 9.8

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h = v² sin²Ф / 2g

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3 years ago
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Answer:

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Explanation:

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radius of wheel, R = 0.65 m

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I = 0.5 x 7 x 0.65 x 0.65 + 2.1 x 0.41 x 0.41

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B. the continents were once joined together..... this is pangaea
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