Question

According to Coulomb's law, when the distance between two point charges doubles, what happens to the electric force acting between the charges?

Answer 1

Answer:

If the distance between charges is doubled, then the Force will become one-fourth.

F' = F/4

Explanation:

The Coulomb's Law gives the relation for the attractive or repulsive forces between two charges. The relation or formula is given as follows:

F = kq₁q₂/r²

where,

F = Attractive or Repulsive forces between the charges

k = Coulomb's Constant

q₁ = magnitude of 1st charge

q₂ = magnitude of 2nd charge

r = distance between charges

If we keep the magnitude of charges constant then the relation between Force an Distance between charges will be:

F α 1/r²

So, it is clear from this relation that if the distance between charges is doubled, then the Force will become one-fourth.

F' = F/4