You are looking to find gravitational energy, the formula for that is (height)(weight)(acceleration due to gravity). In your case I️t will be (3)(2)(9.8)= 58.8 Joules
Answer:
The weight of the person would increase
Explanation:
The Universal Law of Gravitation gives the magnitude of the force between the masses of two objects (m1 and m2) separated a given distance "d" as:
![F_g=G\,\frac{m_1*m_2}{d^2}](https://tex.z-dn.net/?f=F_g%3DG%5C%2C%5Cfrac%7Bm_1%2Am_2%7D%7Bd%5E2%7D)
where G is the universal gravitational constant.
Our weight on Earth is this force between the Earth (of mass M) and ourselves (our mass m) at a distance that is the Earth's radius R:
![Weight=G\frac{M*m}{R^2}](https://tex.z-dn.net/?f=Weight%3DG%5Cfrac%7BM%2Am%7D%7BR%5E2%7D)
Now, if we keep all the values equal (mass of the Earth M and our mass m) except for the distance between the center of the Earth and our center of gravity (the radius of the Earth), we are going to have now a smaller radius (r) in the formula above:
![Weight=G\frac{M*m}{r^2}](https://tex.z-dn.net/?f=Weight%3DG%5Cfrac%7BM%2Am%7D%7Br%5E2%7D)
and dividing by a smaller number (r is smaller than R), will render a larger quotient. This means that the actual force (weight) will become larger, so the weight would clearly increase.
Answer:
3.18 Nm
Explanation:
Given that:
Radius (r) = 15cm = 15/100 = 0.15m
θ = 45°
Applied force (F) = 30 N
The Torque can be obtained using the relation :
T = rF * sinθ
T = 0.15 * 30 * sin(45)
T = 0.15 * 30 * 0.7071067
T = 3.18198015
T = 3.18 Nm
Answer:
The lever is a movable bar that pivots on a fulcrum attached to a fixed point. The lever operates by applying forces at different distances from the fulcrum, or a pivot. As the lever rotates around the fulcrum, points farther from this pivot move faster than points closer to the pivot.
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