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vovangra [49]
3 years ago
14

QUICK PLZ I NEED TO TURN IT IN

Physics
2 answers:
Anni [7]3 years ago
8 0
The answer i got is 133.3 but i’m not completely sure . I got that because to get velocity i’m pretty sure it’s distance over time. So in between 8 and 10 minutes it’s 9 minutes. I pretty much just did 1200 divided by 9.
Serjik [45]3 years ago
7 0

Answer:800

Explanation:800 - 1600 = 800

Don’t really if this what you asked for but I tried.

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We would like to use the relation V(t)=I(t)R to find the voltage and current in the circuit as functions of time. To do so, we u
Delvig [45]

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Explanation:

The explanation or solution is given in the attach document

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4 years ago
A positive charge is placed within the sphere without touching it. You grounded the sphere by touching it with your finger. Then
zhuklara [117]

Answer:

Negative

Explanation:

If a negatively charged object is used to charge a neutral object by induction, then the neutral object will acquire a positive charge. And if a positively charged object is used to charge a neutral object by induction, then the neutral object will acquire a negative charge:

We have a neutral sphere

1) Electrons are attracted to the positive charge

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4 years ago
THIS IS DUE IN 5 MINUTES IM BEGGING YOU PLEASE ANSWER
Archy [21]

Answer:

the answer is A or 900

Explanation:

what u have to do is add all the forces together and then u get ur answer.

4 0
3 years ago
Type of bacteria that attacks the throat- causing fever sore throat rash
Law Incorporation [45]

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Streptococcus Pyogenes

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4 0
3 years ago
A 770-kg boulder is raised from a quarry 106 m deep by a long uniform chain having a mass of 575 kg . This chain is of uniform s
Bas_tet [7]

Answer:

(a) a_{y}= 1.931m/s^{2}

(b) t=10.478s

Explanation:

For Part(a)

Apply ∑Fy=ma

T-Mg=Ma_{y} \\

Solve for a

a_{y}=\frac{T-Mg}{M}=\frac{2.80mg-Mg}{M} \\a_{y}=\frac{(2.80*575kg-1345kg)}{1345kg}*(9.80m/s^{2} )\\a_{y}= 1.931m/s^{2}

For Part(b)

Assume the maximum acceleration (maximum tension upwards is greater than the weight of the chain+boulder)

As the given data

a_{y}=1.931m/s^{2}\\  y-y_{o}=106m\\v_{oy}=0

Using equation of simple motion

y-y_{o}=v_{oy}t+(1/2)a_{y}t^{2} \\t=\sqrt{\frac{2(y-y_{o})}{a_{y}} }\\ t=\sqrt{\frac{2(106m)}{1.931m/s^{2} } }\\t=10.478s

4 0
4 years ago
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