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Volgvan
3 years ago
13

In a hypothetical atom, electron N transitions between energy levels, giving off orange light in the transition. In the same ato

m, electron P gives off violet light when it transitions between energy levels. Did electron N or electron P have a transition that covered a greater energy difference? The electromagnetic spectrum has been provided to assist you in answering the question, and you should reference info from the spectrum in your answer. Be clear and fully explain how you arrived at your answer.

Chemistry
2 answers:
Zielflug [23.3K]3 years ago
6 0

Answer : Electron P has greater energy difference than the Electron N.

Explanation :  

Wavelength range of violet light = 400 - 500 nm

Wavelength range of orange light = 600 - 700 nm

The Planck's equation is,

E=\frac{h\times c}{\lambda}

where,

E = energy of light

c = speed of light

\lambda = wavelength of light

According to the Planck's equation, wavelength and energy follow inverse relation. As the wavelength increases, energy decreases.

From the given spectrum, the wavelength of violet light is less. We conclude that When electron P gives violet light on transition it means that energy difference between the energy level was high.

From the given spectrum, the wavelength of orange light is more. We conclude that When electron N  gives orange light on transition it means that energy difference between the energy level was low.

So, Electron P which gives violet light on transition has greater energy difference than the Electron N.


USPshnik [31]3 years ago
3 0
<h2>Answer:</h2>

Yes, electron N or electron P have a transition that covered a greater energy difference.

<h3>Explanation:</h3>
  • N electron giving orange light means light wave of 650 to 700 nm wavelength according to electromagnetic spectrum.
  • P electron giving Violet light means light wave with a wavelength of 400 nm.
  • As wave length and energy of a wave is inversely proportional to each other.
  • It means N electron light with long wavelength has low energy.
  • P electron light with short wave length has high energy.
  • Hence both electrons have transitions of great energy difference.
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For 100.0 mL of a solution that is 0.040M CH3COOH and 0.010 M CH3COO, what would be the pH after adding 10.0 mL 50.0 mM HCl?
damaskus [11]

Answer:

The pH of the buffer is 3.90

Explanation:

The mixture of a weak acid CH3COOH and its conjugate base CH3COO produce a buffer that follows the equation:

pH = pKa + log [A-] / [HA]

<em>Where pH is the pH of the buffer, pKa is the pKa of acetic acid (4.75), and [A-] could be taken as the moles of the conjugate base and [HA] the moles of thw weak acid.</em>

<em />

To solve this question we need to find the moles of the CH3COOH and CH3COO- after the reaction with HCl:

CH3COO- + HCl → CH3COOH + Cl-

<em>The moles of CH3COO- are its initial moles - the moles of HCl added</em>

<em>And moles of CH3COOH are its initial moles + moles HCl added</em>

<em />

Moles CH3COO-:

Initial moles  = 0.100L * (0.010mol / L) = 0.00100moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.000500 moles

Moles CH3COOH:

Initial moles  = 0.100L * (0.040mol / L) = 0.00400moles

Moles HCl = 0.010L * (0.050mol / L) = 0.000500 moles

Moles CH3COO- = 0.003500 moles

pH is:

pH = 4.75 + log [0.000500] / [0.00350]

<em>pH = 3.90</em>

<em />

<h3>The pH of the buffer is 3.90</h3>
3 0
3 years ago
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