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3 years ago

Which step of mitosis involves the chromosomes lining up in the center of the cell?

Physics

2 answers:

gizmo_the_mogwai [7]3 years ago

5 0

Answer:

Metaphase

Explanation:

During metaphase,chromosome line up in the middle of the cell.

gladu [14]3 years ago

5 0

Chromosomes line up at the metaphase.

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A child is sitting on the outer edge of a merry-go-round that is 1.5 m in diameter. If the merry-go-round makes 3.2 rev/min, wha

Troyanec [42]

Answer:

the velocity of the kid is 5.6 m/s

Explanation:

r is the radius and w is the frequency.

so we should know that the diameter is 18m and the diameter is equal to two times the radius, so r = 18m/2 = 9m

we should also know that the circumference of a circle is equal to c = 2pi*r, so each revolution has this length. if the kid does 5.9 revolutions in one minute then the kid spins at v = 5.9*2pi*9m/min

so we want to write this in meters per second and this means that we need to divide it by 60!

v = (5.9*2pi*9/60)m/s = 5.56 m/s

so your answer will be 5.6 m/s glad i could help!

4 0

2 years ago

Read 2 more answers

Write down the kirchhoff's laws in the adjoining circuit , find the current in each resistors

lapo4ka [179]

Answer:

You need a motor and a battery

Explanation:

4 0

3 years ago

How many atoms are in a lightbulb

Gre4nikov [31]

It depends on the size, material, shape, etc.

8 0

3 years ago

One Newton is equivalent to<br> A. 1 kg/s2<br> B. 1 kg*m/s<br> C. 1 kg*m/s2<br> D. 1 kg/s

Shalnov [3]

Answer:

1 N =

$1kg \: ms { }^{ - 2}$

Explanation:

force = mass × acceleration

1N = 1kg × 1 m/s^2 =

$1kg \: ms {}^{ - 2}$

7 0

3 years ago

An electron is trapped between two large parallel charged plates of a capacitive system. The plates are separated by a distance

Nataly_w [17]

Answer:

0.4cm

Explanation:

First, you calculate the dis acceleration of the electron generated by the potential difference between the plates:

$F=ma\\\\qE=ma\\\\q\frac{V}{d}=ma\\\\a=\frac{qV}{md}$ (1)

q: charge of the electron = 1.6*10^-19 C

V: potential difference between plates = 100V

m: mass of the electron

d: distance between parallel plates = 1cm = 0.01m

by replacing the values of the parameters you obtain:

$a=\frac{(1.6*10^{-19C})(100V)}{(9.1*10^{-31})(0.01m)}=1.75*10^{15}\frac{m}{s^2}$

you use this value in the following kinematic equation:

$v^2=v_o^2-2ax$ (2)

v: final velocity = 0m/s (until the electron stops)

from the equation (2) you calculate x, the distance traveled by the electron. But before you calculate the initial velocity of the electron by using the following equation:

$K=10eV\\\\\frac{1}{2}mv_o^2=10eV\\\\v_o=\sqrt{\frac{2(10(1.602*10^{-19}J))}{9.1*10^{-31}kg}}\\\\v_o=1.87*10^6\frac{m}{s}$

Next, you replace vo in (2) to obtain x:

$0=v_o^2-2ax\\\\x=\frac{v_o^2}{2a}=\frac{(1.87*10^6m/s)^2}{2(1.75*10^{15}m/s^2)}=0.001m=0.1cm$

Then, the electron travels 0.1cm from the middle of the region between the parallel plates, hence, the distance between the electron and the negatve plate is:

0.5cm-0.1cm=0.4cm

6 0

4 years ago