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Amanda [17]
3 years ago
14

At the bottom of a mine shaft, the air

Physics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:2900

Explanation:

I think

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Three disks are spinning independently on the same axle without friction. Their respective rotational inertias and angular speed
ololo11 [35]

Answer:

3/7 ω

Explanation:

Initial momentum = final momentum

I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet

-Iω + 6Iω - 2Iω = 7I ωnet

3Iω = 7I ωnet

ωnet = 3/7 ω

The final angular velocity will be 3/7 ω counterclockwise.

7 0
3 years ago
Read 2 more answers
A brand of earplugs reduces the sound intensity level by 27 dB.By what factor do these earplugs reduce the acoustic intensity?
Fofino [41]

Answer:

Explanation:

27dB = 2.7 B

So I / I₀ = 10⁻²°⁷ ,  I₀ is intensity of main sound and I is intensity after reduction.

= 1.99 X 10⁻³

So intensity will reduce by 1.99 X 10⁻³  .

3 0
3 years ago
A sphere has an unknown amount of charge distributed uniformly at a distance of 0.56cm from the center of the of the sphere, the
Mars2501 [29]
2+2+2+2+22++2+2+2+2+222+2++2c2+2+2+2+2+2
7 0
4 years ago
A go-cart is traveling at a rate of 25 m/sec for 20 seconds. How far will the go cart travel?
notsponge [240]

Answer:

Distance travel by go-cart = 500 meter

Explanation:

Given:

Speed of go cart = 25 m/s

Time travel = 20 seconds

Find:

Distance travel by go-cart

Computation:

Distance = Speed x time

Distance travel by go-cart = Speed of go cart x Time travel

Distance travel by go-cart = 25 x 20

Distance travel by go-cart = 500 meter

4 0
3 years ago
During the first 6 years of its operation, the Hubble Space Telescope circled the Earth 37,000 times, for a total of 1,280,000,0
oksian1 [2.3K]

Answer:

v = 384km/min

Explanation:

In order to calculate the speed of the Hubble space telescope, you first calculate the distance that Hubble travels for one orbit.

You know that 37000 times the orbit of Hubble are 1,280,000,000 km. Then, for one orbit you have:

d=\frac{1,280,000,000km}{37,000}=34,594.59km

You know that one orbit is completed by Hubble on 90 min. You use the following formula to calculate the speed:

v=\frac{d}{t}=\frac{34,594.59km}{90min}=384.38\frac{km}{min}\approx384\frac{km}{min}

hence, the speed of the Hubble is approximately 384km/min

5 0
3 years ago
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