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elena-s [515]
3 years ago
15

Which formula represents an organic compound?

Chemistry
2 answers:
Leto [7]3 years ago
5 0

<u>Answer:</u> The correct answer is Option 2.

<u>Explanation:</u>

Organic compounds are defined as those compounds in which a covalent bond is present between hydrogen and carbon atom. They are basically known as hydrocarbons. If any atom other than hydrogen and carbon is present, it is not considered as an organic compound.

From the given options:

<u>Option 1:</u> CaH_2

A, calcium atom is present, so it is not considered as an organic compound.

<u>Option 2:</u> C_4H_8

As., only carbon and hydrogen atom is only present, so it is considered as an organic compound.

<u>Option 3:</u> H_2O_2

As, oxygen atom is present, so it is not considered as an organic compound.

<u>Option 4:</u> P_2O_5

As, phosphorous and oxygen atoms are present, so it is not considered as an organic compound.

From the above information, the correct answer is Option 2.

coldgirl [10]3 years ago
3 0

(2) C4H8 because it contains a carbon
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3 years ago
Which term defines the following: moles of solute mass of solvent in kg?
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3 years ago
Automobile airbags contain solid sodium azide, NaN 3 , that reacts to produce nitrogen gas when heated, thus inflating the bag.
Yuri [45]

<u>Answer:</u> The value of work for the system is -935.23 J

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of sodium azide = 16.5 g

Molar mass of sodium azide = 65 g/mol

Putting values in above equation, we get:

\text{Moles of sodium azide}=\frac{16.5g}{65g/mol}=0.254mol

The given chemical equation follows:

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

By Stoichiometry of the reaction:

2 moles of sodium azide produces 3 moles of nitrogen gas

So, 0.254 moles of sodium azide will produce = \frac{3}{2}\times 0.254=0.381mol of nitrogen gas

To calculate volume of the gas given, we use the equation given by ideal gas, which follows:

PV=nRT

where,

P = pressure of the gas = 1.00 atm

V = Volume of the gas = ?

T = Temperature of the gas = 22^oC=[22+273]K=295K

R = Gas constant = 0.0821\text{ L. atm }mol^{-1}K^{-1}

n = number of moles of nitrogen gas = 0.381 moles

Putting values in above equation, we get:

1.00atm\times V=0.381mol\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 295K\\\\V=\frac{0.381\times 0.0821\times 295}{1.00}=9.23L

To calculate the work done for expansion, we use the equation:

W=-P\Delta V

We are given:

P = pressure of the system = 1atm=1.01325\times 10^5Pa     (Conversion factor:  1 atm = 101325 Pa)

\Delta V = change in volume = 9.23L=9.23\times 10^{-3}m^3     (Conversion factor:  1m^3=1000L )

Putting values in above equation, we get:

W=-1.01325\times 10^5Pa\times 9.23\times 10^{-3}m^3\\\\W=-935.23J

Hence, the value of work for the system is -935.23 J

7 0
4 years ago
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