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2 years ago

What reagent is used to detect the presence of starch?

Chemistry

1 answer:

LenaWriter [7]2 years ago

3 0

Answer:iodine solution

Explanation: it is because in the presece of starch iodine will turn blue/black

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What is the molar mass of cholesterol if 0.00105 mol weighs 0.406 g?

goblinko [34]

<h3>Answer: 386.67 g/mol </h3>

Explanation:

Molar Mass = Mass ÷ Mole

= 0.406 g ÷ 0.00105 mol

= 386.67 g/mol

∴ molar mass of cholesterol = 386.67 g/mol

5 0

3 years ago

When a 2.00 g sample of KCl is dissolved in water in a calorimeter that has a total heat capacity of 1.28 kJ ⋅ K − 1 , the tempe

Alchen [17]

Answer : The molar heat of solution of KCl is, 17.19 kJ/mol

Explanation :

First we have to calculate the heat of solution.

$q=c\times (\Delta T)$

where,

q = heat produced = ?

c = specific heat capacity of water = $1.28kJ/K$

$\Delta T$ = change in temperature = 0.360 K

Now put all the given values in the above formula, we get:

$q=1.28kJ/K\times 0.360K$

$q=0.4608kJ=460.8J$

Now we have to calculate the molar heat solution of KCl.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy change = ?

q = heat released = 460.8 J

m = mass of $KCl$ = 2.00 g

Molar mass of $KCl$ = 74.55 g/mol

$\text{Moles of }KCl=\frac{\text{Mass of }KCl}{\text{Molar mass of }KCl}=\frac{2.00g}{74.55g/mole}=0.0268mole$

Now put all the given values in the above formula, we get:

$\Delta H=\frac{460.8J}{0.0268mole}$

$\Delta H=17194.029J/mol=17.19kJ/mol$

Therefore, the molar heat of solution of KCl is, 17.19 kJ/mol

7 0

3 years ago

gold(iii) chloride reacts with Antimony(III) oxide and water to produce Gold Antimony(V) oxide and Hydrochloric acid balanced eq

zhuklara [117]

Balanced equation below

5 0

3 years ago

Aluminum reacts with a certain nonmetallic element to form a compound with the general formula AIX; where element X is a diatomi

lora16 [44]

Explanation:

I thought oxygen

mark me a brain list

6 0

2 years ago

An 8.0 L sample of neon gas at 300. K exerts a pressure of 900. kPa. If the gas is compressed to 2.0 L and the temperature is ra

svetoff [14.1K]

Answer:

7200 kPa

Explanation:

Applying,

PV/T = P'V'/T'................ Equation 1

Where P = Initial pressure of neon gas, V = Initial volume of neon gas, T = Initial temperature of neon gas, P' = Final pressure of neon gas, V' = Final volume of neon gas, T' = Final Temperature of neon gas

Make P' the subject of the equation

P' = PVT'/V'T.............. Equation 2

Given: P = 900 kPa, V = 8.0 L, T = 300 K, V' = 2.0 L, T' = 600 K

Substitute these values into equation 2

P' = (900×8×600)/(2×300)

P' = 7200 kPa

6 0

3 years ago