Here is what we know:
a = ?, s = ?, u = 18.1m/s, v = zero/rest, t = 7.0s, m = 2110kg
(a = acceleration, s= displacement, u = initial velocity, v = final velocity, t = time and m is mass)
Now we choose a kinematic formula. Since we know v, u and t, we will use the formula: v = u+at and rearrange it so that we can find a.
a = v-u/t
a = 0-18.1/7.0 = -2.5857...
therefore, a = -2.6m/s
We have our acceleration, now let’s find the net force. To find the force we use one of Newtons laws of motion.
We will use Newtons second law since it describes what happens when one or more forces act upon an object.
F = ma
F = (2110kg)(-2.6m/s)
F = -5486 kg
Therefore the net force F = -5486 N
Answer:
first number is 113 and the second number is 15
Answer:
40 W
Explanation:
The maximum wattage (power) that Mike can use is given by:
where
V is the voltage
I is the maximum current
In this problem, we have:
is the voltage
is the maximum current available
Therefore, the maximum power that could be used is
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