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maw [93]
3 years ago
6

As a result, the total energy in a ____ system (in other words, a system with no external forces) will remain constant

Physics
1 answer:
Alika [10]3 years ago
4 0

Answer:

Isolated or Closed system, both are correct

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Certain neutron stars (extremely dense stars) are believed to be rotating at about 500 rev/s. If such a star has a radius of 17
Alexus [3.1K]

Answer:

7.22 × 10²⁹ kg

Explanation:

For the material to be in place, the gravitational force on the material must equal the centripetal force on the material.

So, F = gravitational force = GMm/R² where M = mass of neutron star, m = mass of object and R = radius of neutron star = 17 km

The centripetal force F' = mRω² where R = radius of neutron star and ω  = angular speed of neutron star

So, since F = F'

GMm/R² = mRω²

GM = R³ω²

M = R³ω²/G

Since ω = 500 rev/s = 500 × 2π rad/s = 1000π rad/s = 3141.6 rad/s = 3.142 × 10³ rad/s and r = 17 km = 17 × 10³ m and G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg²

Substituting the values of the variables into M, we have

M = R³ω²/G

M = (17 × 10³ m)³(3.142 × 10³ rad/s)²/6.67 × 10⁻¹¹ Nm²/kg²

M = 4913 × 10⁹ m³ × 9.872 × 10⁶ rad²/s²/6.67 × 10⁻¹¹ Nm²/kg²

M = 48,501.942 × 10¹⁵ m³rad²/s² ÷ 6.67 × 10⁻¹¹ Nm²/kg²

M = 7217.66 × 10²⁶ kg

M = 7.21766 × 10²⁹ kg

M ≅ 7.22 × 10²⁹ kg

8 0
2 years ago
If you put a penny in each light spot, explain which one will receive the most energy.
SIZIF [17.4K]
If you put a penny in each light spot the penny that the light is shining on will recive the most energy.
8 0
3 years ago
10 points please somebody help me
Anuta_ua [19.1K]
It is the first one?
7 0
3 years ago
Read 2 more answers
Which statement best describes how light waves travel in a uniform medium. A. in straight lines. . B. in extending circles. . C.
Tanya [424]
Light waves travel in straight lines when they are travelling in a uniform medium. This is because the waves are travelling at the same speed.
6 0
3 years ago
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Block A weighs 14 lb and block B weighs 5 lb If B is moving downward with a velocity (vB)1 = 3 ft/s at t = 0, determine the velo
kolezko [41]

Velocity, va2 = 10.5 ft/s

<u>Explanation:</u>

From the figure:

Length of the cable = Sa + 2Sb = l

∴ vₐ = -2vb

Applying the principle of Impulse and momentum in x-direction

mv_x_1 + \int\limits^t_t {F_x} \, dt = mv_x_2

Limit is t1 to t2

-(\frac{14}{32.2}) (2) (3) - T = \frac{14}{32.2} v_y_2                           -(1)

Applying the principle of Impulse and momentum in y-direction

mv_y_1 + \int\limits^t_t {F_y} \, dt = mv_y_2

Limit is t1 to t2

(\frac{5}{32.2}) (3) - 2T + 3 = -\frac{5}{32.2} \frac{v_y_2}{2}                            -(2)

Solving equation (1) and (2), we obtain

T = 1.6lb

va2 = 10.5 ft/s

8 0
3 years ago
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