Answer:
20 metros en 4 segundos.
Explicación:
Un pasajero quiere subirse a un microbús que está parado y corre tras él con una velocidad uniforme de 5 m / s por lo que tomará el autobús 4 segundos si el autobús está a 20 metros de distancia porque la persona se mueve con una velocidad uniforme de 5 metros en uno. segundo para que la persona pueda alcanzar 20 metros de distancia en 4 segundos, por lo que podemos concluir que la persona llega al autobús en 4 segundos.
Answer:
Explanation:
We shall apply theory volume conservation to calculate rate of flow of water .
a ) A₁ V₁ = A₂V₂ , A₁ and A₂ are area of cross section and V₁ , V₂ are velocity of flow at two places along pipe.
b ) π x 1.2² x 4.75 = π x 0.6² x V₂
V₂ = 4 X 4.75
= 19 m /s
c )
For finding pressure we shall apply Bernoulli's theorem
P₁ + 1 / 2 ρ v₁² = P₂ + 1 /2 ρ v₂² + ( h₂ - h₁ ) ρ g
P₁ and P₂ are pressure at ground and second floor , v₁ and v₂ are velocity at two floors and h₁ , h₂ are height of two floors . ρ is density of water.
4.1 x 10⁵ + 1/2 x 1000 x 4.75² = P₂ + 1/2 x 1000 x 19² + 5.2 x 1000 x 9.8
4.1 x 10⁵ + .11 x 10⁵ = P₂ + 1.8 X 10⁵ + .51 X 10⁵
P₂ = 1.9 X 10⁵
= 1.9 atm .
Answer:
H = 0.673
Explanation:
given,
side of cubical crate = 0.74
weight of the crate = 600 N
magnitude of force = 330 N
the Horizontal distance of its Center of mass
= 0.74/2
= 0.37
Let the required Height be H
By Balancing the Torques, we get
H x 330 N = 0.37 x 600
330 H = 222
H = 0.673
hence, the height above the floor where force is acting is equal to 0.673 m
The circuit must be closed. That means from one battery terminal, all the way around the circuit to the other battery terminal, there must be conductors all the way.