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alexgriva [62]
3 years ago
10

What is equall to E=MC​

Physics
2 answers:
NeTakaya3 years ago
6 0

Answer: Nothing is, if im not mistake

Explanation:

11111nata11111 [884]3 years ago
5 0

Answer:

C=E/M

Explanation:

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A student is subjected to a reaction force of 10 N northward from a 5 kg block while pushing the block over a smooth, level sufa
harkovskaia [24]

Answer:

The Analysis Model approach we focus on in this revision lays out a standard set of situations that appear in most

physics problems. These situations are based on an entity in one of four simplification models: particle, system,

rigid object, and wave. Once the simplification model is identified, the student thinks about what the entity is

doing or how it interacts with its environment. This leads the student to identify a particular Analysis Model for the

problem. For example, if an object is falling, the object is recognized as a particle experiencing an acceleration due

to gravity that is constant. The student has learned that the Analysis Model of a particle under constant acceleration

describes this situation. Furthermore, this model has a small number of equations associated with it for use in starting problems, the kinematic equations presented in Chapter 2. Therefore, an understanding of the situation has led

to an Analysis Model, which then identifies a very small number of equations to start the problem, rather than the

myriad equations that students see in the text. In this way, the use of Analysis Models leads the student to identify

the fundamental principle. As the student gains more experience, he or she will lean less on the Analysis Model

approach and begin to identify fundamental principles directly.

To better integrate the Analysis Model approach for this edition, Analysis Model descriptive boxes have been

added at the end of any section that introduces a new Analysis Model. This feature recaps the Analysis Model introduced in the section and provides examples of the types of problems that a student could solve using the Analysis

Model. These boxes function as a “refresher” before students see the Analysis Models in use in the worked examples

for a given section.

Worked examples in the text that utilize Analysis Models are now designated with an AM icon for ease of reference. The solutions of these examples integrate the Analysis Model approach to problem solving. The approach is

further reinforced in the end-of-chapter summary under the heading Analysis Models for Problem Solving, and through

the new Analysis Model Tutorials that are based on selected end-of-chapter problems and appear in Enhanced

WebAssign.

Analysis Model Tutorials. John Jewett developed 16

Explanation:

5 0
3 years ago
What will be the fundamental frequency and first three overtones for a 26cm long organ at 20°C if it is open ( at 20°C, the spee
kakasveta [241]

Explanation:

The frequency of an organ pipe if it is open is given by :

f=\dfrac{nv}{2l}

v is speed of sound in air is 343 m/s at 20°C

For fundamental frequency, n = 1

f=\dfrac{1\times 343}{2\times 0.26}\\\\f=659.61\ Hz

First overtone frequency,

f_1=2f\\\\f_1=2\times 659.61\\\\f_1=1319.22\ Hz

Second overtone frequency,

f_2=3f\\\\f_2=3\times 659.61\\\\f_2=1978.83\ Hz

Third overtone frequency

f_3=4f\\\\f_3=4\times 659.61\\\\f_3=2638.44\ Hz

Hence, this is the required solution.

3 0
3 years ago
A researcher is interested in determining the average length and weight of loblolly pine tree needles in the southeast United St
Anna [14]

Answer:

Experimentation

Explanation:

The loblolly pine tree is a member of the yellow pine group which is grown in plantations for commercial production of timber.The tree itself can reach a height of 40 meters with a truck of 1 meter in diameter.Pines have long needle-like leaves held in bundles. A researcher can measure the length of the needles, count the number of needles in a bundle, and measure the length of the sheath.Loblloly pine needles measure up to 17 cm long.The researcher can also weigh a bundle and determine the weight of the needles.This is field experiment that will require a measuring device for weight and length so observation alone won't provide the needed data.

8 0
3 years ago
Read 2 more answers
A potter's wheel has the shape of a solid uniform disk of mass 13.0 kg and radius 1.25 m. It spins about an axis perpendicular t
Fittoniya [83]

Answer:10.82 kg-m^2

Explanation:

Given

Mass of solid uniform disk M=13 kg

radius of disk r=1.25 m

mass of lump m=1.7 kg

distance of lump from axis r_0=0.63

Moment of inertia is the distribution of mass from the axis of rotation

Initial moment of inertia of disk I_1=\frac{Mr^2}{2}

I_1=\frac{13\times 1.25^2}{2}=10.15 kg-m^2

Final moment of inertia I_f=Moment of inertia of disk+moment of inertia of lump about axis

I_f=\frac{Mr^2}{2}+mr_0^2

I_f=10.15+1.7\times 0.63^2

I_f=10.15+0.674

I_f=10.82 kg-m^2

3 0
4 years ago
7. A stick of length L and mass M is hanging at rest from its top edge from a ceiling hinged at that point so that it is free to
Lilit [14]

Answer:

The distance from the top of the stick would be 2l/3

Explanation:

Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.

Applying impulse momentum theorem for linear momentum.

FΔt = m(Wl/2), since velocity of center of mass of rod  = Wl/2

Similarly applying impulse momentum theorem per angular momentum about H

FΔt * x = I * W

Where FΔt * x represents the impulsive torque and I is the moment of inertia

F Δt.x = (ml² . W)/3

Substituting FΔt

M(Wl/2) * x = (ml². W)/3

1/x = 3/2l

x = 2l/3

8 0
3 years ago
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