The average thickness of a sheet of the paper is 0.1 mm.
The number of ice blocks that can be stored in the freezer is 80 blocks of ice.
<h3>Average thickness of a sheet of the paper</h3>
The average thickness of a sheet of the paper is calculated as follows;
average thickness = 6 mm/60 sheets = 0.1 mm /sheet
Thus, the average thickness of a sheet of the paper is 0.1 mm.
<h3>Volume of each block of ice</h3>
Volume = 10 cm x 10 cm x 4 cm
Volume = 400 cm³
<h3>Volume of the freezer</h3>
Volume = 40 cm x 40 cm x 20 cm = 32,000 cm³
<h3>Number of ice blocks that can be stored</h3>
n = 32,000 cm³/400 cm³
n = 80 blocks of ice
Thus, the number of ice blocks that can be stored in the freezer is 80 blocks of ice.
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Answer:
option E
Explanation:
given,
I is moment of inertia about an axis tangent to its surface.
moment of inertia about the center of mass
.....(1)
now, moment of inertia about tangent
...........(2)
dividing equation (1)/(2)
the correct answer is option E
Answer:
b) se duplica
Explanation:
The disk is moving with constant angular velocity, let's call it 
.
The linear velocity of a point on the disk is given by
where r is the distance of the point from the axis of rotation.
In this problem, the object is moved at a distance twice as far as the initial point, so
Therefore, the new linear velocity is
So, the velocity has doubled, and the correct answer is
b) se duplica
Answer:
Because of heavy mass
Explanation:
When force acts on a body it tends to accelerate the body. The acceleration produced in the body depends on two things:
1). Magnitude of force
2). Mass of the body
F= ma
⇒ a = F/m
As the force exerted on earth and another object are the equal in magnitude but opposite in direction. This forces will accelerate the object toward the earth but can't accelerate the earth as earth has very high mass.
a = F/m
This force tends to accelerate the earth but but due to earth's inertia the earth does not accelerate.
Answer:
Explanation:
The question here is that if sneezy hands from a similar rope while delivering presents at the earth's equator, what will be the tension in the rope be. Here is the solution:The tension on the rope when it is at pole, T= 455 NTo find, the tension, t= mgTo solve for mass, m= t/g. Substituting this we have, m=455/9.8. m=46.43 kgAssume that the downwards acceleration is, a= -46.43 m/s^2.T = mg + maT = (46.43 kg) ( 9.8 m/s^2) - (46.43 kg) (-46.43 m/s^2)T = 455.01 kg-m/s^2 - -2155.74 kg-m/s^2T = 2610.75 kg-m/s^2 = 2610.75 N
