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lora16 [44]
2 years ago
8

Try the same filtering method with the salt water. What happened? Taste the

Chemistry
2 answers:
enyata [817]2 years ago
3 0

Yeah, what? I don't think Brainly knows that. Maybe you should taste the filtered salt water and find out the answer.

Lerok [7]2 years ago
3 0

Answer:

It should, well, taste less salty or even like fresh water if it is filtered enough

Explanation:

Depending on how you filter it, the salt should separate out of the water

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Pcl3+H2O=H3PO3+Hcl=?​
beks73 [17]

Answer:

PCl3 + 3H2O → HPO(OH)2 + 3HCl. Phosphorus(III) chloride react with water to produce phosphorous acid and hydrogen chloride.

Explanation:

7 0
3 years ago
Read 2 more answers
Based on your knowledge of energy conservation, which of the following statements is true?
Julli [10]
C. both a and b

If a light bulb can last longer with the same amount of energy it is given, that means it can use less energy to do the same job compared to one that does not last longer with the same amount of energy it is given. It is much like how a more fuel efficient car will be able to go farther on the same tank of gas, but if you pair it with a car that doesn't have as great of an mpg, when they go the same distance, the car with the greater mpg spends less fuel.

If you don't have to use the energy when you aren't utilizing it, then you can conserve the energy for when you do need it.
3 0
3 years ago
How many grams are in 3.14 moles of PI₃?
OverLord2011 [107]

Answer:

\boxed {\boxed {\sf 1290 \ g \ PI_3}}

Explanation:

We want to convert from moles to grams, so we must use the molar mass.

<h3>1. Molar Mass</h3>

The molar mass is the mass of 1 mole of a substance. It is the same as the atomic masses on the Periodic Table, but the units are grams per mole (g/mol) instead of atomic mass units (amu).

We are given the compound PI₃ or phosphorus triiodide. Look up the molar masses of the individual elements.

  • Phosphorus (P): 30.973762 g/mol
  • Iodine (I): 126.9045 g/mol

Note that there is a subscript of 3 after the I in the formula. This means there are 3 moles of iodine in 1 mole of the compound PI₃. We should multiply iodine's molar mass by 3, then add phosphorus's molar mass.

  • I₃: 126.9045 * 3=380.7135 g/mol
  • PI₃: 30.973762 + 380.7135 = 411.687262 g/mol

<h3>2. Convert Moles to Grams</h3>

Use the molar mass as a ratio.

\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

We want to convert 3.14 moles to grams, so we multiply by that value.

3.14 \ mol \ PI_3 *\frac {411.687262 \ g \ PI_3}{ 1 \  mol \ PI_3}

The units of moles of PI₃ cancel.

3.14 *\frac {411.687262 \ g \ PI_3}{ 1 }

1292.698 \ g\ PI_3

<h3>3. Round</h3>

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, that is the tens place.

  • 1292.698

The 2 in the ones place tells us to leave the 9.

1290 \ g \ PI_3

3.14 moles of phosphorous triiodide is approximately equal to <u>1290 grams of phosphorus triodide.</u>

4 0
3 years ago
The study of the composition of matter is?
NemiM [27]

Chemistry. More specifically, analytical chemistry.

6 0
3 years ago
1. Consider the following equilibrium system: C(s) + CO2(g) 2CO(g)
ser-zykov [4K]

Answer:

a) equilibrium shifts towards the right

b) equilibrium shifts towards the right

c) equilibrium shifts towards the left

d) has no effect on equilibrium position

e) has no effect on equilibrium position

Explanation:

A reversible reaction may attain equilibrium in a closed system. A chemical system is said to be in a state of dynamic equilibrium when the rate of forward reaction is equal to the rate of reaction.

According to Le Chateliers principle, when a constraint such as a change in temperature, pressure, volume or concentration is imposed upon a system in equilibrium, the equilibrium position shifts in such a way as to annul the constraint.

When the concentration of reactants is increased, the equilibrium position is shifted towards the right hand side and more products are formed. For an endothermic reaction, the reverse reaction is favoured by a decrease in temperature. Increase in pressure has no effect on the system since there are equal volumes on both sides of the reaction equation. Similarly, the addition of a catalyst has no effect on the equilibrium position since it speeds up both the forward and reverse reactions to the same extent.

3 0
3 years ago
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