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3 years ago

A tow truck pulls a 7,800 N car 5m out of a ditch in 6.5 seconds. How much power does the

Physics

1 answer:

rosijanka [135]3 years ago

6 0

Answer:

p=6000W

Explanation:

p=w/t

w=f*d=7800*5=39000 J

therefore,

p=39000/6.5=6000 W

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Fill in the blank please I’m very confused

Reika [66]

For the third one on the top you can put to get solar panels on your roof

4 0

3 years ago

Marked as brainiest if correct

Naily [24]

Answer:

I think the the answer is creating and layout and template style ( C )

Explanation:

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7 0

3 years ago

Consider a wire of a circular cross-section with a radius of R = 3.17 mm. The magnitude of the current density is modeled as J =

Sloan [31]

Answer:

The current is $I = 8.9 *10^{-5} \ A$

Explanation:

From the question we are told that

The radius is $r = 3.17 \ mm = 3.17 *10^{-3} \ m$

The current density is $J = c\cdot r^2 = 9.00*10^{6} \ A/m^4 \cdot r^2$

The distance we are considering is $r = 0.5 R = 0.001585$

Generally current density is mathematically represented as

$J = \frac{I}{A }$

Where A is the cross-sectional area represented as

$A = \pi r^2$

=> $J = \frac{I}{\pi r^2 }$

=> $I = J * (\pi r^2 )$

Now the change in current per unit length is mathematically evaluated as

$dI = 2 J * \pi r dr$

Now to obtain the current (in A) through the inner section of the wire from the center to r = 0.5R we integrate dI from the 0 (center) to point 0.5R as follows

$I = 2\pi \int\limits^{0.5 R}_{0} {( 9.0*10^6A/m^4) * r^2 * r} \, dr$

$I = 2\pi * 9.0*10^{6} \int\limits^{0.001585}_{0} {r^3} \, dr$

$I = 2\pi *(9.0*10^{6}) [\frac{r^4}{4} ] | \left 0.001585} \atop 0}} \right.$

$I = 2\pi *(9.0*10^{6}) [ \frac{0.001585^4}{4} ]$

substituting values

$I = 2 * 3.142 * 9.00 *10^6 * [ \frac{0.001585^4}{4} ]$

$I = 8.9 *10^{-5} \ A$

5 0

4 years ago

What is the electric force acting between two charges of -0.0050 C and 0.0050 C that are 0.025 m apart?

nika2105 [10]

Answer:

(A) $-3.6\times 10^8\ N$

Explanation:

Given:

Charge of one particle (q₁) = -0.0050 C

Charge of another particle (q₂) = 0.0050 C

Separation between them (d) = 0.025 m

We know that, from Coulomb's law, electric force acting between two charged particles is given as:

$F_e=\dfrac{kq_1q_2}{d^2}\\\\Where,k\to Coulomb's\ constant = 9\times 10^9\ N\cdot m^2/C^2$

Plug in the given values and solve for electric force, $F_e$ . This gives,

$F_e=\frac{(9\times 10^9\ N\cdot m^2/C^2) (-0.0050\ C)(0.0050\ C)}{(0.025\ m)^2}\\\\F_e=\frac{-2.25\times 10^{-4}\times 10^9}{6.25\times 10^{-4}}\ N\\\\F_e=-3.6\times 10^8\ N$

Therefore, option (A) is correct. Negative sign implies that the nature of electric force is attraction.

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3 years ago

compare the numbers of each subatomic particle found in both diagrams and then list what makes hydrogen diffrent from hellium

Cloud [144]

The helium atom is found to contain more particles than the hydrogen atom.

<h3>What is a subparticle?</h3>

An atom is composed of particles and these particles are electrons protons and neutrons. The collective name for these particles is the subatomic particles.

Now we know that the helium atom contains more sub atomic particles than the atom of hydrogen. This is because, the helium atom contains two neutrons and two protons as well as two electrons. On the other hand, the hydrogen atom contains one neutron and one proton as well as one electron.

Thus, the helium atom is found to contain more particles than the hydrogen atom.

Learn more about helium atom:brainly.com/question/4945478

#SPJ1

7 0

1 year ago