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Iteru [2.4K]
3 years ago
11

Please Help!!!

Physics
2 answers:
mr_godi [17]3 years ago
4 0
<span>I THINK ITS Tell them to increase the amplitude of their sound waves.
</span>
OleMash [197]3 years ago
3 0

Technically, what you want is for them to increase the amplitude
of their sound waves. 

But chances are, if you SAY it to them in that way, they will have
no idea what you're talking about, they will think you're pretty weird,
and they'll continue to mutter and mumble. 

So, although it's not technically elegant, you're better off just saying
"Hey ! Talk louder willya !"
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TEA [102]

Answer:

1.25 m/s

Explanation:

m1v1+m2v2=m1v1f+m2v2f

(1425*13)+(1175*0)=(1425*v1f)+(1175*14.25)

18525+0=1425(v1f)+16743.75

1781.25=1425(v1f)

v1f=1.25 m/s

4 0
3 years ago
Explain how waves, energy, and matter are related
Stels [109]

Answer:

Mechanical waves need matter to transfer energy while electromagnetic waves do not. ... Waves change direction when they move from one material into another (matter) through the process of refraction. The wave will change direction when the speed of the wave changes.

3 0
3 years ago
A glider with mass 0.24 kg sits on a frictionless horizontal air track, connected to a spring of negligible mass with force cons
shepuryov [24]

Answer:

v=2.556m/s

Explanation:

From the conservation of mechanical energy

K_{E1}+U_1=K_{E2}+U_2

\frac{1}{2}m*v_1^2+\frac{1}{2}*K*x_1^2=\frac{1}{2}m*v_2^2+\frac{1}{2}*K*x_2^2

x_2=0.08m

v_1=0 m/s

Solve to velocity v2

m*v_2^2=k*x_1^2-k*x_2^2

v^2=\frac{k}{m}*(x_1^2-x_2^2)

v^2=\frac{5.5N/m}{0.24kg}*(0.54m^2-0.080^2)

v=\sqrt{6.54m^2/s^2}=2.556m/s

4 0
3 years ago
What relationship exists between the amplitude of a wave and amount of disturbance in the water?
guapka [62]
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6 0
3 years ago
The angular momentum of an electron in each of its orbits must be some multiple of:
Nastasia [14]
The Bohr's proposal for the angular momentum of an electron in Bohr's model of the hydrogen atom is:

L=(n*h)/(2π), where n is the number of the energy level and h is the Planck's constant. This equation shows us the quantization of angular momentum of the electron. So the correct answer is the second one: Planck's constant. 
7 0
3 years ago
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