Test are not directly used to make measurements, I mean you could use them to put 4 mL of a substance in, but not to measure out 4 mL, like with graduated cylinders. Rulers can be used to measure the length of something, like the number of inches. And a thermometer will help you measure the temperature of something.
Answer:

Explanation:
This question asks us to find the new volume if the pressure changes. Therefore, we use Boyle's Law, which states that pressure and the volume of the gas are inversely proportional. The formula is:

We know that the original sample of gas occupies 4.5 liters at a pressure of 1.63 atmospheres. We know that the pressure was changed to 2.4 atmospheres, but we don't know the volume. Substitute all known values into the formula.

Since we are solving for the new volume (V₂), we need to isolate the variable. It is being multiplied by 2.4 atmospheres and the inverse of multiplication is division. Divide both sides by 2.4 atm.


The units of atmospheres (atm) cancel.



The smallest number of significant figures in the original measurements is 2, so our answer must have the same. For the number we found, that is the tenths place.
The 5 in the hundredth place tells us to round the 0 up to a 1.

The volume of the neon gas when the pressure is changed to 2.4 atmospheres is <u>3.1 Liters.</u>
Answer:
Explanation:
1 standard deviation range will look like: [average - SD, average + SD]
Here the miximum value will be: average - SD = 2.6 - 0.80 = 1.80 ml
and the maximum value will be: average + SD = 2.6 + 0.80 = 3.40ml
Hydrogen i think. the orbital of hydrogen is peculiar
Answer:
0.501 L
Explanation:
To solve this problem we will use Boyle,s Law. According to this law "The volume of given amount of gas is inversely proportional to applied pressure at constant temperature".
V∝ 1/P
V= K/P
VP=K
Here the K is proportionality constant.
so,
P1V1 = P2V2
P= pressure
V= volume
Given data:
P1= 1 atm
V1= 461 mL
P2= 0.92 atm
V2= ? (L)
To solve this problem we have to convert the mL into L first.
1 L = 1000 mL
461/1000= 0.461 L
Now we will put the values in the equation,
P1V1 = P2V2
V2= P1V1/ P2
V2= 1 atm × 0.461 L / 0.92 atm
V2= 0.501 L